Question

定义闪光距离的函数，该函数采用参数时间间隔（秒）并使用公式计算：

the distance(in kilometers) = time interval(in seconds) * 330 / 1000.

以千米为单位的闪电距离并将其返回。距离应四舍五入到整数。返回值的闪光距离功能必须已经四舍五入。

我有这样的程序，但有些事情是非常错误的，我需要帮助。我该怎么办？

def flash_distance (number_ms):
     flash_distance = (number_ms * 330/1000)
     round return (flash_distance * 330/1000)
   
distance_ms = 330

distance = int (input ("How many seconds it took seeing the lightning flash hearing?"))

print ("lightning distance in kilometers:" + str (flash_distance (distance_ms)))

Answer 1

我认为以下代码可以解决您的问题。在您的代码中，distance_ms已分配给330，因此用户分配的变量distance将无效，这通常不会发生。

def flash_distance (number_ms): 
     flash_distance = (number_ms * 330/1000)  
     return round (flash_distance)

distance_ms = int (input ("How many seconds it took seeing the lightning flash hearing?"))

print ("lightning distance in kilometers:" + str (flash_distance (distance_ms)))

以python计算的flash距离

1 个答案: