Question

有没有办法让两个名为list1和list2的列表能够在另一个列表中查找一个条目的位置。即。

list_one = ["0", "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

list_two = ["h","e","l","l","o"]

我的目的是允许用户输入一个单词，然后程序将转换为与list_one中的字母条目对应的一组数字

所以如果用户确实输入了你好，那么计算机将返回85121215（作为条目的位置）

有可能这样做吗

Answer 1

查找列表中项目的位置不是一个非常有效的操作。对于这种任务，dict是更好的数据结构。

>>> d = {k:v for v,k in enumerate(list_one)}
>>> print(*(d[k] for k in list_two))
8 5 12 12 15

如果您的list_one始终只是字母表，则按字母顺序排列，使用内置函数ord可能会更好，更简单。

Answer 2

添加到@ wim的答案，可以通过简单的理解来完成。

>>> [list_one.index(x) for x in list_two]
[8, 5, 12, 12, 15]

Answer 3

x.index(i)返回列表i的元素x的位置

print("".join([str(list_one.index(i)) for i in list_two]))
85121215

Answer 4

在列表中使用list_one = ["0", "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"] string = "hello" positions = [list_one.index(c) for c in string] print(positions) # [8, 5, 12, 12, 15]：

WebDriverWait

Answer 5

你可以迭代思考清单：

DECLARE @query VARCHAR(max)
DECLARE @years VARCHAR(max)

SELECT  @years = STUFF(( SELECT DISTINCT '],[' + ltrim(str(Years)) FROM 
                 #Inquires ORDER BY '],[' + ltrim(str(Years)) desc FOR XML 
                 PATH('')), 1, 2, '') + ']'    

SET @query = 'INSERT INTO Table_Name SELECT * 
              FROM (SELECT ReportDate, Company, EventType, Years,Months#,
                    Months,Inquires FROM #Inquires
                    WHERE Company = ''Company_Name'')t PIVOT (SUM(Inquires) 
                    FOR Years IN ('+@years+')) AS pvt ORDER BY Company, Months#'

EXECUTE (@query)

但是Wim的答案更优雅！

从python中的另一个列表中的一个列表中查找元素

5 个答案: