Question

我（尝试）利用CMake的生成器表达式来支持基于Fortran项目的编译器供应商的 生成时 编译器标志配置。

不幸的是，虽然相关的documentation描述了如何在C和C ++项目中完成（分别参见C_COMPILER_ID和CXX_COMPILER_ID逻辑表达式），但没有提到Fortran模拟。

我已确认没有Fortran_COMPILER_ID生成器表达式，在使用时会发出以下错误：

CMake Error at CMakeLists.txt:<line number> (target_compile_options):
  Error evaluating generator expression:

    $<Fortran_COMPILER_ID:GNU>

  Expression did not evaluate to a known generator expression

是否可以为Fortran项目估算此行为？

编辑：

期望行为的最低范例

cmake_minimum_required( VERSION 3.2 ) 

project( myProject LANGUAGES Fortran )

set( fortran_module_directory "${CMAKE_BINARY_DIR}/modules" CACHE PATH "directory for fortran modules" )
file( MAKE_DIRECTORY ${fortran_module_directory} ) 
set( CMAKE_Fortran_MODULE_DIRECTORY ${fortran_module_directory} )

set( myProject_GNU_DEBUG_flags "flag1" "flag2" )
set( myProject_GNU_RELEASE_flags "flag3" "flag4" )
set( myProject_Intel_DEBUG_flags "flag5" "flag6")
set( myProject_Intel_RELEASE_flags "flag7" "flag8" )
# other compilers    

add_library( myProject STATIC 
             ${CMAKE_CURRENT_SOURCE_DIR}/src/mySource.f90
             ${CMAKE_CURRENT_SOURCE_DIR}/src/myOtherSource.f90 )

target_include_directories( myProject PUBLIC ${fortran_module_directory} )

target_compile_options( njoy PRIVATE 
$<$<Fortran_COMPILER_ID:GNU>:
    $<$<CONFIG:Debug>:${myProject_GNU_DEBUG_flags}>>
    $<$<CONFIG:Release>:${myProject_GNU_RELEASE_flags}>>>
$<$<Fortran_COMPILER_ID:Intel>:
    $<$<CONFIG:Debug>:${myProject_Intel_DEBUG_flags}>>
    $<$<CONFIG:Release>:${myProject_Intel_RELEASE_flags}>>>
# other compilers
)

Answer 1

我从HDF5 CMakeLists.txt的灵感中发现了一种可行的方法。例如：

set (Fortran_COMPILER_ID CMAKE_Fortran_COMPILER_ID)

target_link_libraries(target PUBLIC
  $<$<STREQUAL:"${Fortran_COMPILER_ID}","GNU">:"-lgfortran">
  $<$<STREQUAL:"${Fortran_COMPILER_ID}","Intel">:"-lifcore">
  )

逼近Fortran_COMPILER_ID CMake生成器表达式

1 个答案: