swift 3中的值对

Question

var par = [[Double]]()

par.append(Array(stride(from: -1, through: 10, by: 1.0)))

//par[0] == [-1.0, 0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]

par.append(Array(stride(from: -10, through: 1, by: 1.0)))

//par[1] == [-10.0, -9.0, -8.0, -7.0, -6.0, -5.0, -4.0, -3.0, -2.0, -1.0, 0.0, 1.0]
//there could be more much more arrays in par…

//Total combinations, 144 in this case

var c: Int = 0
c = par[0].count
for i in 1 ..< par.count {
c *= par[i].count
}

for i in 0 ..< c {
//?
}

嗨！问题是用par [0]，par [1]，......制作数组的最简单方法是什么？在这种情况下12x12：[ - 1.0，-10.0]，[ - 1.0，-9.0]，...，[10.0,1.0]，但它可能是2x20,2x10x50,10x10x20x20 ......