按成对的顺序排序

Question

我有一组排名，按组和排名排序：

Group | Rank
------------
  A   |  1
  A   |  2
  A   |  3
  A   |  4
  A   |  5
  A   |  6
  B   |  1
  B   |  2
  B   |  3
  B   |  4
  C   |  1
  C   |  2
  C   |  3
  C   |  4
  C   |  5
  D   |  1
  D   |  2
  D   |  3
  D   |  4

我希望按组和排名顺序排列组， n每组排名（此处，n = 2）：

Group | Rank
------------
  A   |  1
  A   |  2
  B   |  1
  B   |  2
  C   |  1
  C   |  2
  D   |  1
  D   |  2
  A   |  3
  A   |  4
  B   |  3
  B   |  4
  C   |  3
  C   |  4
  D   |  3
  D   |  4
  A   |  5
  A   |  6
  C   |  5

我已经使用循环和表变量实现了所需的结果（此处粘贴的代码因为我在SQL小提琴中出现了非描述性语法错误）：

CREATE TABLE Rankings([Group] NCHAR(1), [Rank] INT)

INSERT Rankings
VALUES 
('A',1),
('A',2),
('A',3),
('A',4),
('A',5),
('A',6),
('B',1),
('B',2),
('B',3),
('B',4),
('C',1),
('C',2),
('C',3),
('C',4),
('C',5),
('D',1),
('D',2),
('D',3),
('D',4)

-- input
DECLARE @n INT = 2 --number of group rankings per rotation
-- output
DECLARE @OrderedRankings TABLE([Group] NCHAR(1), Rank INT)

-- 

-- in-memory rankings.. we will be deleting used rows
DECLARE @RankingsTemp TABLE(GroupIndex INT, [Group] NCHAR(1), Rank INT)
INSERT @RankingsTemp 
SELECT 
  ROW_NUMBER() OVER (PARTITION BY Rank ORDER BY [Group]) - 1 AS GroupIndex,
  [Group],
  Rank
FROM Rankings
ORDER BY [Group], Rank

-- loop variables
DECLARE @MaxGroupIndex INT = (SELECT MAX(GroupIndex) FROM @RankingsTemp)
DECLARE @RankingCount INT = (SELECT COUNT(*) FROM @RankingsTemp)
DECLARE @i INT

WHILE(@RankingCount > 0)
BEGIN
  SET @i = 0;
  WHILE(@i <= @MaxGroupIndex)
  BEGIN
    INSERT INTO @OrderedRankings
    ([Group], Rank)
    SELECT TOP(@n)
      [Group],
      Rank
    FROM @RankingsTemp
    WHERE GroupIndex = @i;

    WITH T AS (
      SELECT TOP(@n) *
      FROM @RankingsTemp
      WHERE GroupIndex = @i
    );
    DELETE FROM T

    SET @i = @i + 1;
  END
  SET @RankingCount = (SELECT COUNT(*) FROM @RankingsTemp)
END

SELECT @RankingCount as RankingCount, @MaxGroupIndex as MaxGroupIndex

-- view results
SELECT * FROM @OrderedRankings

如何使用基于集合的方法（无循环，无表变量）实现所需的排序？

我正在使用SQL Server Enterprise 2008 R2。

修改：为了澄清，我需要每组不超过n行才能连续显示。此查询的目标是在顺序读取时产生排序，相对于排名，提供每个组的相等表示（每次n行）。

Answer 1

也许是这样...... SQL FIDDLE

Order by
 Ceiling(rank*1.0/2), group, rank

上面的工作小提琴（列名略有变化）

更新：被int math烧掉了......现在应该工作。通过乘以1.0将int强制转换为十进制，因此隐式转换不会丢弃我需要使天花板正确舍入的余数。

Answer 2

假设您的排名数量相对较少，这将有效：

Order by
  case when rank <= n then 10
    when rank <= 2*n then 20
    when rank <= 3*n then 30
    when rank <= 4*n then 40
    when rank <= 5*n then 50 --more cases here if needed
    else 100 
  end
, group
, rank