Question

我有一个名为＆＃34;规划＆＃34;的sql表。 whchi包含id_place，id_event，date_event。我用symfony2编写了这段代码来发送按地点分组的事件的日期。

$query2 = $em->createQueryBuilder();
 $query2->select("p.libPlace ,  p.idPlace ")
        ->from('AppBundle:Place', 'p')
        ->leftJoin('AppBundle:Planning', 'pl', 'WITH', 'pl.idPlace = p.idPlace')
        ->where('pl.idCevent = :id')

        ->setParameter('id', $idEvent)
        ->groupBy('p.idPlace');
$q2 = $query2->getQuery();
$places = $q2->getResult();

$taille = sizeof($places);   

 $j=0; $a=array();
for ($i=0; $i<= $taille-1; $i++)
{ 

$query4 = $em->createQueryBuilder();
$query4->select(" z.dateEventPlace dateEventPlace")
        ->from('AppBundle:Planning', 'z')
        ->where('z.idCevent = :id')
        ->andWhere('z.idPlace = :idp')
        ->setParameter('id', $idEvent)
        ->setParameter('idp', $places[$i]['idPlace'])
        ->orderBy('dateEventPlace', 'ASC');
$q4 = $query4->getQuery();
$planning = $q4->getResult();

$p[$j]=$places[$i];
$j++;
$p[$j]=$planning;
$j++;

}return array('places' =>  $p);

我得到了这个json回复：

places":[
{"libPlace":"Le Colis\u00e9e","idPlace":1},
[{"dateEventPlace":"2017-03-19T08:09:00+0000"},{"dateEventPlace":"2017-03-19T14:19:00+0000"},{"dateEventPlace":"2017-03-24T14:08:00+0000"}],
{"libPlace":"ABC","idPlace":2},
[{"dateEventPlace":"2017-03-22T14:10:00+0000"},{"dateEventPlace":"2017-03-24T16:20:00+0000"}]
]

我希望得到这样的东西：

places":[
{
"libPlace":"Le Colis\u00e9e","idPlace":1,"times":[
{"dateEventPlace":"2017-03-19T08:09:00+0000"},{"dateEventPlace":"2017-03-19T14:19:00+0000"}]
},
{
"libPlace":"ABC","idPlace":2,"times":[ 
{"dateEventPlace":"2017-03-22T14:10:00+0000"}]
}
]

任何解决方案？

从symfony2发送嵌套数组json到angular2

0 个答案: