Question

我有一个标记化单词列表，我正在搜索它中的一些单词并将附近的3个元素存储到找到的单词中。代码是：

Words_to_find - 要查找的单词列表

令牌 - 我必须从words_to_find

中找到的大型列表

for x in words_to_find:
        if x in tokens:
            print "Matched word is", x
            indexing = tokens.index(x)
            print "This is index :", indexing
            count = 0
            lower_limit = indexing - 3
            upper_limit = indexing + 3
            print "Limits are", lower_limit,upper_limit 
            for i in tokens:
                if count >= lower_limit and count <= upper_limit:
                    print "I have entered the if condition"
                    print "Count is : ",count
                    wording = tokens[count]
                    neighbours.append(wording)
                else:
                    count +=1
                    break
                count +=1
           final_neighbour.append(neighbours)
    print "I am in access here", final_neighbour

我无法找到此代码中的错误。我正在采取下限和上限并尝试将其保存在列表中并列出其中的列表（final_neighbour）。请帮我找到问题。提前致谢

Answer 1

我们可以使用切片来获取邻居而不是使用计数进行迭代。

tokens = [u'प्रीमियम',u'एंड',u'गिव',u'फ्रॉम',u'महाराष्ट्रा',u'मुंबई',u'इंश्योरेंस',u'कंपन‌ी',u'फॉर',u'दिस']
words_to_find = [u'फ्रॉम',u'महाराष्ट्रा']
final_neighbours = {}
for i in words_to_find:
    if i in tokens:
       print "Matched word : ",i
       idx = tokens.index(i)
       print "this is index : ",idx
       idx_lb = idx-3
       idx_ub = idx+4
       print "Limits : ",idx_lb,idx_ub
       only_neighbours =  tokens[idx_lb : idx_ub]
       only_neighbours.remove(i)
       final_neighbours[i]= only_neighbours

for k,v in final_neighbours.items():
    print "\nKey:",k
    print "Values:"
    for i in v:
       print  i,

 Output:
  Matched word :  फ्रॉम
  this is index :  3
  Limits :  0 7
  Matched word :  महाराष्ट्रा
  this is index :  4
  Limits :  1 8

  Key: महाराष्ट्रा
  Values:
  एंड गिव फ्रॉम मुंबई इंश्योरेंस कंपन‌ी 
  Key: फ्रॉम
  Values:
  प्रीमियम एंड गिव महाराष्ट्रा मुंबई इंश्योरेंस

Answer 2

每个单词的邻居都会发生变化。因此，每个单词都为空。并且count也应该被分配给indexing-3，如果它的＆gt; = 0则为lower_limit，否则为0，因为找到的单词中的前三个和后三个单词是你需要的。

for x in words_to_find:
    neighbours=[] # the neighbour for the new word will change, therefore make it null!
    if x in tokens:
        print "Matched word is", x
        indexing = tokens.index(x)
        print "This is index :", indexing
        lower_limit = indexing - 3
        upper_limit = indexing + 3
        count = lower_limit if lower_limit >=0 else 0# lower_limit starts from the index-3 of the word found!
        print "Limits are", lower_limit,upper_limit,count
        for i in tokens:
            if count >= lower_limit and count <= upper_limit:
                print "I have entered the if condition"
                print "Count is : ",count
                wording = tokens[count]
                neighbours.append(wording)
            else:
                count +=1
                break
            count +=1
        final_neighbour.append(neighbours)
    print "I am in access here", final_neighbour

示例IO（一些随机令牌和words_to_find用于测试目的）：

tokens='hi this is hi keerthana hello world hey hi hello'.split()
words_to_find=['hi','hello']
I am in access here [['hi', 'this', 'is', 'hi'], ['is', 'hi', 'keerthana', 'hello', 'world', 'hey', 'hi']]

<强>建议

您可以使用列表切片来获取匹配单词之前和之后的3个单词。这也将提供所需的输出！

lower_limit = lower_limit if lower_limit >=0 else 0
neighbours.append(tokens[lower_limit:upper_limit+1])

即，

final_neighbour=[]
for x in words_to_find:
    neighbours=[] # the neighbour for the new word will change, therefore make it null!
    if x in tokens:
        print "Matched word is", x
        indexing = tokens.index(x)
        print "This is index :", indexing
        lower_limit = indexing - 3
        upper_limit = indexing + 3
        lower_limit = lower_limit if lower_limit >=0 else 0# lower_limit starts from the index-3 of the word found!
        print "Limits are", lower_limit,upper_limit
        neighbours.append(tokens[lower_limit:upper_limit+1])
        final_neighbour.append(neighbours)
    print "I am in access here", final_neighbour

希望它有所帮助！

Answer 3

您在for循环中有以下行

neighbours.append(wording)

什么是“邻居”??

你应该初始化它（特别是在循环之外...更喜欢在你定义标记和Words_to_find的代码的开头使用）如下面的附加语句

neighbours[]

从列表中查找元素并将附近的元素存储在列表中 - Python

3 个答案: