Question

我正在尝试使用其他列表在zip list上进行查找和替换，但出于某种原因，我似乎无法理解这个easy问题。所以，首先，我有一个拉链列表，看起来像（说myzip_list）：

("this is a united string divided here","this is the value of the string),("this is a multiply string2 united here","this is the value of the string2)....

现在，我有另一个列表，看起来像这样（说replace_list）：

[['united', '##sharp'], ['divided', '##blunt'], ['multiply', '##med']]

我想要做的是将myzip_list [0]元素替换为double hash中的replace_list值。因此，作为最终结果，我想最终得到：

myzip_list = ("this is a ##sharp string ##blunt here","this is the value of the string),("this is a ##med string2 ##sharp here","this is the value of the string2)....

如果有人能指出我正确的方向，我将不胜感激......

修改的

如果replace_list只包含一个单词，则下面的网络答案确实有效。因此，例如，如果replace_list看起来像：

[['united all', '##sharp'], ['divided me', '##blunt'], ['multiply all', '##med']]

如果myzip_list看起来像：

("this is a united all string divided me here","this is the value of the string),("this is a multiply all string2 united all here","this is the value of the string2)....

..然后网络方法失败。

Answer 1

l = [['united', '##sharp'], ['divided', '##blunt'], ['multiply', '##med']]
d = dict(l)

>>> d
{'multiply': '##med', 'divided': '##blunt', 'united': '##sharp'}

tups = [("this is a united string divided here","this is the value of the string"),("this is a multiply string2 united here","this is the value of the string2")]

[[' '.join([d.get(i,i) for i in sub.split()]) for sub in tup] for tup in tups]

输出

[['this is a ##sharp string ##blunt here', 'this is the value of the string'],
 ['this is a ##med string2 ##sharp here', 'this is the value of the string2']]

Answer 2

zip函数是它自己的逆函数，所以如果你有zip列表将它自己解压缩！通过像zip(*your_list)之类的命令，然后使用下面的代码！

import re
myzip_list="(this is a united string divided here,this is the value of the string),(this is a multiply string2 united here,this is the value of the string2)"
tempword=[w for w in re.split('\W', myzip_list) if w]
replace_list=[['united', '##sharp'], ['divided', '##blunt'], ['multiply', '##med']]
my_dict=dict(replace_list)
lst=my_dict.keys()

for i in range(len(tempword)) :
 for j in lst:
   if tempword[i]==j:
       tempword[i]=my_dict[j]

print ' '.join(tempword)

样本：

"this is a ##sharp string ##blunt here this is the value of the string this is a ##med string2 ##sharp here this is the value of the string2"

如果您不想使用re，请使用re.split('\W', myzip_list)更改my_ziplist.split()并删除impoer re。

list查找并替换另一个列表中的元素

2 个答案: