Question

我有如下表格

create table #temp
( 
 a int null,
b int null,
c int null,
d int null
)

insert into #temp values (0,0,0,0)
insert into #temp values (0,1,0,0)
insert into #temp values (0,0,0,1)
insert into #temp values (0,1,0,0)

我试过

select * from(
(select count(*)  a from #temp where a=1 group by a) dt1 cross join
(select count(*)  b from #temp where b=1 group by b) dt2 cross join
(select count(*)  c from #temp where c=1 group by c) dt3 cross join
(select count(*)  d from #temp where d=1 group by d) dt4 
)

但没有获得任何输出

我希望得到如下所示的输出

a  b  c  d
0  2  0  1

如何实现这一目标？

Answer 1

试试这个：

DECLARE @temp TABLE( a int , b int , c int , d int )
insert into @temp values (0,0,0,0),(0,1,0,0),
(0,0,0,1),(0,1,0,0)

SELECT SUM(a) a,SUM(b) b,SUM(c) c,SUM(d) d FROM @temp

希望它有所帮助。：）

Answer 2

IF OBJECT_ID('tempdb..#TEMP') IS NOT NULL
DRop Table #TEMP

CREATE TABLE #TEMP
( 
A INT NULL,
B INT NULL,
C INT NULL,
D INT NULL
)

INSERT INTO #TEMP VALUES (0,0,0,0)
INSERT INTO #TEMP VALUES (0,1,0,0)
INSERT INTO #TEMP VALUES (0,0,0,1)
INSERT INTO #TEMP VALUES (0,1,0,0)

SELECT * FROM #TEMP

SELECT SUM(A)A,SUM(B)B,SUM(C)C,SUM(D)D FROM #TEMP

Answer 3

如果值仅为0和1，那么使用只需使用SUM：

select sum(a), sum(b), sum(c), sum(d) from #temp;

如果可以有更多其他值，并且您只想计算1，则可以使用sum上的case：

select sum(case when a = 1 then 1 else 0 end),
    sum(case when b = 1 then 1 else 0 end),
    sum(case when c = 1 then 1 else 0 end),
    sum(case when d = 1 then 1 else 0 end)
from #temp;

来自多个sql的SQL单行结果集

3 个答案: