Question

select C.customerId,(C.lastName+', '+C.firstName) as CustomerName, C.companyName, 
D.companyName+' ('+D.lastName+','+D.firstName+')' 
as "Parent CompanyName(Last, First)",S.siteId, S.nickName as siteName, 
dbo.GetSiteTelemetryBoxList(s.siteId) as "DeviceId's", 
dbo.GetSiteTelemetryBoxSKUList(S.siteId,0) as SKU
from Site S
INNER JOIN Customer C ON S.customerId = C.customerId 
INNER JOIN Customer D ON D.customerId = C.parentCustomerId
where S.createDate between DATEADD(DAY, -65, GETUTCDATE()) and GETUTCDATE()
order by C.customerId, S.siteId

上面的查询返回如下所示的值：

CID     CustomerName      companyName           Parent CompanyName(Last, First)                 SiteName                    DeviceId        SKU
888296  DeYoung, Scott    DeYoung Farms         Mercier Valley Irrigation (Mercier,Ralph)       H E east                    200241        NETB12WR
890980  Rust, Marcus      NULL                  Chester Inc. (Young,Scott)                      Byroad east                 346370        NETB12WR
890980  Rust, Marcus      NULL                  Chester Inc. (Young,Scott)                      Byroad west                 345431        NETB12WR
891094  Pirani, Mark      A Pirani Farm         AMX Irrigation (Burroughs,Michael)              hwy 64 south                333721        UNKNOWN
891094  Pirani, Mark      A Pirani Farm         AMX Irrigation (Burroughs,Michael)              HWY 64 North                250162        NETB12WR
891094  Pirani, Mark      A Pirani Farm         AMX Irrigation (Burroughs,Michael)              HWY 64 West                 250164        NETB12WR
891094  Pirani, Mark      A Pirani Farm         AMX Irrigation (Burroughs,Michael)              HWY 64 East                 250157        NETB12WR
891430  Gammil, Bob       Gammil FArms          AMX Irrigation (Burroughs,Michael)              angel                       333677        UNKNOWN
891430  Gammil, Bob       Gammil FArms          AMX Irrigation (Burroughs,Michael)              cemetery                    333564        UNKNOWN

我现在面临的问题是，如果customerId / Name在结果集中重复。应连接SiteName，deviceId，SKU以将数据表示为一个值。例如，Mark Pirani行看起来像

 CID   CustomerName  ...   SiteName                                               DeviceId's                   ...
891904 Pirani, Mark  ...   hwy 64 south, HWY 64 North, HWY 64 West, HWY 64 East   333721,250162,250164,250157  ...

Answer 1

您可以使用类似的内容转换行，将行转换为连续字符串：

 select
   distinct  
stuff((
    select ',' + u.username
    from users u
    where u.username = username
    order by u.username
    for xml path('')
),1,1,'') as userlist
from users
group by username

Answer 2

我认为这比SQL代码问题更多是C#查询问题，或者更合适我认为在查询级别而不是代码级别解决此问题更有效。在我的头顶，你可以使用SELECT DISTINCT或GROUP BY条款。

以下是解决此问题的另一个StackOverflow问题 - How do I (or can I) SELECT DISTINCT on multiple columns?

Answer 3

我做了一些挖掘，并找到了一些方法来实现它。基本上，对此的简单解决方案是使用mysql的group_concat函数。这些链接讨论了如何为SQL Server实现group_concat。您可以根据自己的要求选择一个。

Simulating group_concat MySQL function in Microsoft SQL Server 2005? - 此主题讨论了实现它的几种方法。
Flatten association table to multi-value column? - 这个主题讨论了CLR的实现。
http://groupconcat.codeplex.com/ - 这对我来说非常完美。正是我在寻找什么。该项目基本上创建了四个聚合函数，它们共同提供与MySQL GROUP_CONCAT函数类似的功能。

尝试将多行结果集合并为单行

3 个答案: