Question

GET    /status        controllers.Application.handleWebSocketConnection()

以下是相关的源代码。

public WebSocket handleWebSocketConnection() {
    return WebSocket.withActor(new F.Function<ActorRef, Props>() {
        @Override
        public Props apply(ActorRef actorRef) throws Throwable {
            return UserActor.props(actorRef, "");
        }
    });
}

这是我的build.sbt

import play.routes.compiler.InjectedRoutesGenerator
import play.sbt.PlayScala

name := "hello"

version := "1.0"

lazy val `dashboard` = (project in file(".")).enablePlugins(PlayScala)

scalaVersion := "2.11.8"

libraryDependencies ++= Seq(
  jdbc ,
  cache ,
  ws   ,
  specs2 % Test,
  "io.netty" % "netty-all" % "4.0.0"
)

unmanagedResourceDirectories in Test <+=  baseDirectory ( _ /"target/web/public/test" )  

resolvers ++= Seq(
  "scalaz-bintray" at "https://dl.bintray.com/scalaz/releases"
)

routesGenerator := InjectedRoutesGenerator

fork in run := true

我正在使用Play版本2.4.2，所有源代码都在java 8中。我收到以下错误。我不确定我的路线和控制器是怎么回事。我在这里跟随link。

[error] /Users/hello/Documents/java/test_app/conf/routes:8: Cannot use a method returning play.mvc.WebSocket[?0] as a Handler for requests

[error] GET    /status       controllers.Application.handleWebSocketConnection()        

[error] /Users/hello/Documents/java/test_app/conf/routes:8: not enough arguments for method createInvoker: (implicit hif: play.core.routing.HandlerInvokerFactory[play.mvc.WebSocket[?0]])play.core.routing.HandlerInvoker[play.mvc.WebSocket[?0]].

[error] two errors found


[error] (compile:compile) Compilation failed

任何想法？

Answer 1

我没有添加评论所需的代表......所以我们走了：

我想知道指定websocket处理的消息类型是否可以解决问题，请尝试：

public WebSocket<String> handleWebSocketConnection()

这当然是假设你的websocket期望从浏览器进入字符串，就像发送字符串一样。

无法使用方法返回play.mvc.WebSocket作为Play中请求的处理程序？

1 个答案: