Question

我正在为我的C ++类编写一个汽车类程序，而Visual Studio不会使用的唯一部分是＆＃34; string和make＆＃34;。我评论了他们，程序运行得很好。我们的老师要求我们将其拆分为3个单独的页面。标题中发布的错误是MISSING TYPE SPECIFIER。事实证明，所需要的只是＆＃34;使用命名空间std;＆＃34;在car.h文件中。

感谢您的帮助。

    #include "stdafx.h"
    #include <iostream>
    #include <string>
    #include <iomanip>
    #include "Car.h"
    using namespace std;


    int main()
    {
        // Declare car object
        Car myCar;
        int speed = 0, year;
        string make;


        cout << "This program will help you with your Car!" << endl;   //         intro message

        cout << "Please enter the Year" << endl;   // store year
        cin >> year;

        cout << "Please enter the Make of the car" << endl;   // store make
        cin >> make;


        // call member functions to set car year and make.
        myCar.setYear(2013);
        myCar.setMake("Mustang GT");

        // call member functions to get car year and make
        cout << "Your car's current year is: " <<  myCar.getYear() << endl;
        cout << "Your car's current make is: " << myCar.getMake;
        cout << "Your car's current speed is : " << speed << " mph" << endl;





        return 0;
     }

这是Car.h

#pragma once
#ifndef CAR_H
#define CAR_H



// Car class declaration
class Car
{
    private:
        string make;
        int year;
        int speed;

    public:
        int myCar(int year, string make, int speed);

        int setYear(int carYear);

        int setSpeed(int carSpeed);

        string setMake(string carMake);

        int getYear();

        int getSpeed();

        string getMake();

        void accelerate();

        void brake();


};

这是Car.cpp

#include "stdafx.h"
#include <iostream>
#include <string>
#include <iomanip>
#include "Car.h"
using namespace std;


//***
//myCar
//**
int Car::myCar(int year, string make, int speed)
{
    int setYear(int year);
    string setMake(string make);
    return year, make, speed;
}


//**********
// setYear
//*********
int Car::setYear(int carYear)
{
    year = carYear;
    return carYear;

}


//************
// setMake
//************
string Car::setMake(string carMake)
{

    make = carMake;


}
//***    

//***
//setSpeed
//***
int Car::setSpeed(int carSpeed)
{
    speed = carSpeed;
    return carSpeed;


}
//***

//***
//getYear
//***
int Car::getYear()
{

    return year;

}
//***

//***
//getMake
//***
string Car::getMake()
{
    return make;

}


//***
//getSpeed
//***
int Car::getSpeed()
{

    return speed;

}
//***

//***
// Accelerate
//***
void Car::accelerate()
{
    int speed = 0;
    speed += 5;


}
//***

//***
// Brake
//***
void Car::brake()
{
    int speed = 0;
    speed -= 5;

}
//***

Answer 1

在setMake函数中，它被声明为字符串但不返回任何值。我相信你忘了回复过去的价值。

//************
// setMake
//************
string Car::setMake(string carMake)
{

    make = carMake;
    return make; // This line should do the trick

}

我建议下次仔细查看编译器输出的内容，因为它可能会给你一个行号，甚至是问题的函数名称。

旁注：通常设置的函数声明为void，因为它们通常不需要返回任何内容。

错误：缺少类型说明符

1 个答案: