Question

我需要创建一个程序，它得到的数字总和从100到500.

int sum = 0;
for (int i = 1; i <10; i++)
{
    sum = sum + i;
    printf("%d", sum);
}

它应该打印55（1到10之间的数字之和），但它打印出136101521283645。

在此之后，我需要一个能够得到100到500之间数字之和的程序。

Answer 1

这里你只是从1到9做i的总和，并且每次循环都打印出这个总和。

相反，你应该这样做：

int sum = 0;
for (int i = 1; i <= 10; i++)
{
    sum += i;
}
printf("%d", sum);

对于100到500，请执行以下操作：

int sum = 0;
for (int i = 100; i <= 500; i++)
{
    sum += i;
}
printf("%d", sum);

Answer 2

将int sum = 0; for (int i = 1; i <10; i++) { sum = sum + i; } printf("%d", sum);置于循环之外

"use strict";
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window.mymodule = function(mymodule) {};

Answer 3

您应该更改它以便打印最终总和！

int sum = 0;
for (int i = 1; i <10; i++)
{
    sum = sum + i;
}
 printf("%d", sum);

所以你的最终节目（总和从100到500）将是这样的：

int sum = 0;
for (int i = 100; i <500; i++)
{
    sum = sum + i;
}
 printf("%d", sum);

Answer 4

您需要在循环之外移动print语句。每次循环运行时，它都会打印每个结果。

Answer 5

一种简单的方法是：这是它的程序：

public class unoQuini {
    private int sum = 0;
    private static int menor = 1;
    private static int mayor = 5;
    public int getSum() {
      return sum;
    }
    public void setSum(int sum) {
      this.sum = sum;
    }
    public int getMenor() {
      return menor;
    }
    public void setMenor(int menor) {
      this.menor = menor;
    }
    public int getMayor() {
      return mayor;
    }
    public void setMayor(int mayor) {
      this.mayor = mayor;
    }
    public static void main (String Args[]){
      unoQuini unqui = new unoQuini(); 
      int sum2 = 0;
      for (int i = menor; i<= mayor;i++ ){
        sum2 += i;
        unqui.setSum(sum2);
      }
      System.out.println("Suma = "+ unqui.getSum());
    }
}

重要的部分是：

public static void main (String Args[]){
          unoQuini unqui = new unoQuini(); 
          int sum2 = 0;
          for (int i = menor; i<= mayor;i++ ){
            sum2 += i;
            unqui.setSum(sum2);
          }
          System.out.println("Suma = "+ unqui.getSum());
        }

Answer 6

总之，除了10（TO编号）之外，你还可以在for循环中打印数字

int SumOfNumbers(int from, int to)
{
    int sum;
    if(from > to)
    {
       sum = from;
       from = to;
       to = sum
    }
    sum = 0;
    for(int i = from; i <= to; ++i)
       sum += i;
    return sum;
}

然后你就可以调用ur func

了

sum = SumOfNumbers(from, to);
printf("%d\n");

对于两个数字之间的数字的循环和

6 个答案: