在我的jqgrid形式的应用程序中，我想同时上传文件以及发布数据。我在哪里使用 jquery版本作为jquery-3.1.1.js和jqgrid版本作为5.2.0 的。
正如我在intenet上读到的，它无法同时在jqgrid上传文件和发布数据。因此，在提交文件以外的数据后，您可以通过 ajaxFileUpload 方法上传文件。因为我使用的是最新版本的jquery ，它无法通过此功能上传文件。
所以我的问题是： - 1）上面的错误是什么？如何删除它
2）如何在没有ajaxfile上传的情况下在jqgrid上传文件
提前致谢
答案 0 :(得分：0)
我尝试通过jqGrid的'afterSubmit'事件使用ajaxfileupload.js，但错误仍然存在。否则，我以不同的方式得到它。
我用过：
<强> ajaxFileUpload.js
jQuery.extend({
handleError: function( s, xhr, status, e ) {
// If a local callback was specified, fire it
if ( s.error ) {
s.error.call( s.context || window, xhr, status, e );
}
// Fire the global callback
if ( s.global ) {
(s.context ? jQuery(s.context) : jQuery.event).trigger( "ajaxError", [xhr, s, e] );
}
},
createUploadIframe: function(id, uri)
{
//create frame
var frameId = 'jUploadFrame' + id;
var iframeHtml = '<iframe id="' + frameId + '" name="' + frameId + '" style="position:absolute; top:-9999px; left:-9999px"';
if(window.ActiveXObject)
{
if(typeof uri== 'boolean'){
iframeHtml += ' src="' + 'javascript:false' + '"';
}
else if(typeof uri== 'string'){
iframeHtml += ' src="' + uri + '"';
}
}
iframeHtml += ' />';
jQuery(iframeHtml).appendTo(document.body);
return jQuery('#' + frameId).get(0);
},
createUploadForm: function(id, fileElementId, data)
{
//create form
var formId = 'jUploadForm' + id;
var fileId = 'jUploadFile' + id;
var form = jQuery('<form action="" method="POST" name="' + formId + '" id="' + formId + '" enctype="multipart/form-data"></form>');
if(data)
{
for(var i in data)
{
jQuery('<input type="hidden" name="' + i + '" value="' + data[i] + '" />').appendTo(form);
}
}
var oldElement = jQuery('#' + fileElementId);
var newElement = jQuery(oldElement).clone();
jQuery(oldElement).attr('id', fileId);
jQuery(oldElement).before(newElement);
jQuery(oldElement).appendTo(form);
//set attributes
jQuery(form).css('position', 'absolute');
jQuery(form).css('top', '-1200px');
jQuery(form).css('left', '-1200px');
jQuery(form).appendTo('body');
return form;
},
ajaxFileUpload: function(s) {
// TODO introduce global settings, allowing the client to modify them for all requests, not only timeout
s = jQuery.extend({}, jQuery.ajaxSettings, s);
var id = new Date().getTime();
var form = jQuery.createUploadForm(id, s.fileElementId, (typeof(s.data)=='undefined'?false:s.data));
var io = jQuery.createUploadIframe(id, s.secureuri);
var frameId = 'jUploadFrame' + id;
var formId = 'jUploadForm' + id;
// Watch for a new set of requests
if ( s.global && ! jQuery.active++ )
{
jQuery.event.trigger( "ajaxStart" );
}
var requestDone = false;
// Create the request object
var xml = {};
if ( s.global )
jQuery.event.trigger("ajaxSend", [xml, s]);
// Wait for a response to come back
var uploadCallback = function(isTimeout)
{
var io = document.getElementById(frameId);
try
{
if(io.contentWindow)
{
xml.responseText = io.contentWindow.document.body?io.contentWindow.document.body.innerHTML:null;
xml.responseXML = io.contentWindow.document.XMLDocument?io.contentWindow.document.XMLDocument:io.contentWindow.document;
}else if(io.contentDocument)
{
xml.responseText = io.contentDocument.document.body?io.contentDocument.document.body.innerHTML:null;
xml.responseXML = io.contentDocument.document.XMLDocument?io.contentDocument.document.XMLDocument:io.contentDocument.document;
}
}catch(e)
{
jQuery.handleError(s, xml, null, e);
}
if ( xml || isTimeout == "timeout")
{
requestDone = true;
var status;
try {
status = isTimeout != "timeout" ? "success" : "error";
// Make sure that the request was successful or notmodified
if ( status != "error" )
{
// process the data (runs the xml through httpData regardless of callback)
var data = jQuery.uploadHttpData( xml, s.dataType );
// If a local callback was specified, fire it and pass it the data
if ( s.success )
s.success( data, status );
// Fire the global callback
if( s.global )
jQuery.event.trigger( "ajaxSuccess", [xml, s] );
} else
jQuery.handleError(s, xml, status);
} catch(e)
{
status = "error";
jQuery.handleError(s, xml, status, e);
}
// The request was completed
if( s.global )
jQuery.event.trigger( "ajaxComplete", [xml, s] );
// Handle the global AJAX counter
if ( s.global && ! --jQuery.active )
jQuery.event.trigger( "ajaxStop" );
// Process result
if ( s.complete )
s.complete(xml, status);
jQuery(io).unbind();
setTimeout(function(){
try
{
jQuery(io).remove();
jQuery(form).remove();
} catch(e){
jQuery.handleError(s, xml, null, e);
}
}, 100);
xml = null
}
};
// Timeout checker
if ( s.timeout > 0 )
{
setTimeout(function(){
// Check to see if the request is still happening
if( !requestDone ) uploadCallback( "timeout" );
}, s.timeout);
}
try
{
var form = jQuery('#' + formId);
jQuery(form).attr('action', s.url);
jQuery(form).attr('method', 'POST');
jQuery(form).attr('target', frameId);
if(form.encoding)
{
jQuery(form).attr('encoding', 'multipart/form-data');
}
else
{
jQuery(form).attr('enctype', 'multipart/form-data');
}
jQuery(form).submit();
} catch(e)
{
jQuery.handleError(s, xml, null, e);
}
jQuery('#' + frameId).on('load', uploadCallback);
return {abort: function () {}};
},
uploadHttpData: function( r, type ) {
var data = !type;
data = type == "xml" || data ? r.responseXML : r.responseText;
// If the type is "script", eval it in global context
if ( type == "script" )
jQuery.globalEval( data );
// Get the JavaScript object, if JSON is used.
if ( type == "json" )
eval( "data = " + data );
// evaluate scripts within html
if ( type == "html" )
jQuery("<div>").html(data).evalScripts();
return data;
}
});
因此，我将名为“foto”的字段或列配置为接收将通过上传文件传递的图片。
$("#jqGrid").jqGrid({
url: '../load_file_here.php',
editurl: '../edit_file_here.php',
datatype: "json",
...,
...,
colModel: [
{
label: 'Foto',
name: 'foto',
align: 'left',
editable: true,
edittype: 'file',
editoptions: {
enctype: "multipart/form-data"
},
width: 80,
search: false
},
之后，我完成了配置而不是'afterSumit'事件，我放了'afterShowform'并在那里调用一个函数，看看：
$('#jqGrid').navGrid('#jqGridPager',
{
edit: true,
add: true,
del: true,
search: false,
refresh: false,
view: false,
position: "left",
cloneToTop: false
},
{
editCaption: "Editar",
width: "700",
height: "auto",
top: "120",
left: "450",
recreateForm: true,
closeAfterEdit: true,
afterShowForm: takeFile,
errorTextFormat: function (data) {
return 'Error: ' + data.responseText
}
},{ put add here and dele }
因此， afterShowForm 中的函数名为 takeFile ：
$(document).ready(function () {
function takeFile()
{
$("#foto").on("change", function(e) {
e.preventDefault();
$.ajaxFileUpload({
url: "../controller/uploadFile.php",
secureuri: false,
fileElementId:'foto',
dataType: 'json',
success: function (data, status) {
if (data.error == '0')
{
console.log(data.ok);
}else{
console.error(data.error);
}
}
});
});
}
}
最后，简单的 uploadFile.php 是：
<?php
$target_dir = "../../files/";
$target_file = $target_dir . basename($_FILES["foto"]["name"]);
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
$error = "";
$ok = "";
if(isset($_FILES))
{
if (isset($_FILES['foto']))
{
if (move_uploaded_file($_FILES["foto"]["tmp_name"], $target_file)) {
$ok = "The file has been uploaded.";
$error = 0;
} else {
$error = "Failed to upload file ";
}
}
echo json_encode(array(
'ok' => $ok,
'file_name' => basename( $_FILES["foto"]["name"] ),
'error' => $error,
));
?>
就是这样，我希望我在某些方面得到了帮助。感谢