Question

var names = ["andy","amy","randy","ronaldo","nani"];

for(var i = 0;i<names.length;i++){
    console.log("My name is " . names[i]);
}

我想知道这里有什么问题。为什么我不能为零？

Answer 1

JavaScript不是PHP，此处的字符串连接是通过+进行的，而不是.：

var names = ["andy","amy","randy","ronaldo","nani"];

for(var i = 0;i<names.length;i++){
    console.log("My name is " + names[i]);
}

Answer 2

错误是因为

中的.

console.log("My name is " . names[i]);

将此更改为逗号（,）或加号（+）

console.log("My name is ", names[i]);
console.log("My name is " + names[i]);

Answer 3

我认为您将javascript串联与php

混淆了

var names = [“andy”，“amy”，“randy”，“ronaldo”，“nani”];

for(var i in names){
    console.log("My name is " + names[i]); // change . with + here
}

您也可以使用var i in names

最小化循环