Question

我知道我可以通过将“从帐户”和“帐户”存储到变量或其他内容来完成某种循环：但我正在寻找一种更简单的方法。

MainAccount表显然包含1个帐号，该帐号也存储在AccountsInterval表中。在该表中，有一个范围（从帐户到帐户）。没有循环，我很难找到一种方法来获得每个主要帐户的所有二级帐户。有更简单的方法吗？

CREATE TABLE #MainAccounts(id INT IDENTITY(1,1) PRIMARY KEY, MainAccount NVARCHAR(20))
    INSERT INTO #MainAccounts(MainAccount) VALUES('41000')
    INSERT INTO #MainAccounts(MainAccount) VALUES('41010')
    INSERT INTO #MainAccounts(MainAccount) VALUES('41011')
    INSERT INTO #MainAccounts(MainAccount) VALUES('41999')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42000')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42010')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42015')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42020')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42030')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42080')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42310')
    INSERT INTO #MainAccounts(MainAccount) VALUES('42999')
    INSERT INTO #MainAccounts(MainAccount) VALUES('43999')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48000')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48100')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48199')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48200')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48210')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48220')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48299')
    INSERT INTO #MainAccounts(MainAccount) VALUES('48999')
    INSERT INTO #MainAccounts(MainAccount) VALUES('49999')

CREATE TABLE #AccountsInterval(id INT IDENTITY(1,1) PRIMARY KEY, MainAccount NVARCHAR(20), FromAccount NVARCHAR(20), ToAccount NVARCHAR(20))
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('41999', '41000', '41999')
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('42999', '42000', '42999')
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('43999', '41000', '43999')
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('48199', '48000', '48199')
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('48299', '48200', '48299')
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('48999', '48000', '48999')
INSERT INTO #AccountsInterval(MainAccount, FromAccount, ToAccount) VALUES('49999', '41000', '49999')

如果我们使用示例帐户; 41999,42999,43999 ......我们应该得到以下结果。

Main    Secondary
41999   41000
41999   41010
41999   41011
41999   41999
42999   42000
42999   42010
42999   42015
42999   42020
42999   42030
42999   42080
42999   42310
42999   42999
43999   41000
43999   41010
43999   41011
43999   41999
43999   42000
43999   42010
43999   42015
43999   42020
43999   42030
43999   42080
43999   42310
43999   42999
43999   43999

我尝试了多个查询，子查询，而且我无处可去。

Answer 1

这应该在一个查询中执行您想要的操作：

Select  M.MainAccount As Main, S.MainAccount As Secondary
From    #MainAccounts       M
Join    #AccountsInterval   I   On  M.MainAccount = I.MainAccount
Join    #MainAccounts       S   On  Convert(Int, S.MainAccount) Between Convert(Int, I.FromAccount) 
                                                                And     Convert(Int, I.ToAccount)
Order By Main, Secondary

按照问题中的示例，我们可以将结果限制为41999，42999和43999：

Select  M.MainAccount As Main, S.MainAccount As Secondary
From    #MainAccounts       M
Join    #AccountsInterval   I   On  M.MainAccount = I.MainAccount
Join    #MainAccounts       S   On  Convert(Int, S.MainAccount) Between Convert(Int, I.FromAccount) 
                                                                And     Convert(Int, I.ToAccount)
Where   M.MainAccount In ('41999', '42999', '43999')
Order By Main, Secondary

Main    Secondary
41999   41000
41999   41010
41999   41011
41999   41999
42999   42000
42999   42010
42999   42015
42999   42020
42999   42030
42999   42080
42999   42310
42999   42999
43999   41000
43999   41010
43999   41011
43999   41999
43999   42000
43999   42010
43999   42015
43999   42020
43999   42030
43999   42080
43999   42310
43999   42999
43999   43999

Answer 2

app.controller('MapCtrl', function ($scope, $http) {

      $scope.contents = [];

      $http.get('/data4estate/data_model.php')
          .success(function (data) {
              $scope.contents = data;
          });

      $scope.$watch('contents', function () {
          for (i = 0; i < $scope.contents.length; i++) {
              console.log($scope.contents[i].name);
          }
      });
  });

......或者......

select ai.MainAccount as "Main", mi.MainAccount as "Secondary"
from #AccountsInterval ai
join #MainAccounts mi on mi.MainAccount >= ai.FromAccount and mi.MainAccount <= ai.ToAccount

SQL查询 - 显示主帐户和所有辅助帐户

2 个答案: