Question

我使用此查询获取至少3个项目的所有帐户。

SELECT   
        accounts.id,
        accounts.name,
        COUNT(accounts_project_1project_idb) as count
FROM    accounts_project_1_c 
LEFT JOIN accounts ON accounts_project_1accounts_ida = accounts.id
LEFT JOIN project ON accounts_project_1project_idb = project.id
LEFT JOIN project_cstm ON id_c = project.id

GROUP BY accounts_project_1accounts_ida
HAVING COUNT(accounts_project_1project_idb) >= 3
ORDER BY count DESC

其中accounts是帐户表，project是项目表，project_cstm表包含有关项目的更多信息

此请求返回153结果。

但是现在，我希望将联系人链接到一个帐户。如果它存在多个联系人，我真的不在乎，我只想要一个。

SELECT   
        accounts.id,
        accounts.name,
        contacts.first_name,
        contacts.last_name,
        contacts.phone_mobile,
        contacts.phone_work,
        COUNT(accounts_project_1project_idb) as count

FROM    accounts_project_1_c 

LEFT JOIN accounts ON accounts_project_1accounts_ida = accounts.id
LEFT JOIN project ON accounts_project_1project_idb = project.id
LEFT JOIN project_cstm ON id_c = project.id
LEFT JOIN accounts_contacts ON accounts.id = accounts_contacts.account_id
LEFT JOIN contacts ON accounts_contacts.contact_id = contacts.id

GROUP BY accounts_project_1accounts_ida
HAVING COUNT(accounts_project_1project_idb) >= 3
ORDER BY count DESC

此请求返回173个结果。

我真的不明白，使用left join它不应该添加任何行吗？

你能告诉我我做错了什么吗？

非常感谢。

Answer 1

我认为您希望MarriageLicen Year Month Amount 1 2011 Jan 742 2 2011 Feb 796 3 2011 Mar 1210 4 2011 Apr 1376 BusinessLicen Month Year MARRIAGE_LICENSES 1 Jan 2011 754 2 Feb 2011 2706 3 Mar 2011 2689 4 Apr 2011 738成为：

HAVING

您可能也想在HAVING COUNT(DISTINCT accounts_project_1project_idb) >= 3中使用它。

获得至少3个项目的所有帐户，并加入帐户详细信息

1 个答案: