Question

我有2个表，用户和事件：

**Users:**
usersid
age
geo_country
gender


**adbreaks:**
ts
videoid
ads_watched
geo_country
userid

我的问题是：对于1月份的每周，请返回生成最多广告数量的10个视频。

我正在做这个代码吗？

    SELECT video_id, COUNT(ads_watched) AS ad_watched
    FROM (SELECT video_id, MAX(ads_watched) FROM adbreaks) adw
    WHERE WEEK(ts) < WEEK('2017-02-01')
    GROUP BY video_id
    ORDER BY ad_watched DESC
    LIMIT 10;

任何提示都将不胜感激。

谢谢，

和Claudia

Answer 1

“对于1月的每个星期”，您是指每周1次查询还是整个月必须在结果中显示？如果在postgresql中预计每周1次查询：

SELECT video_id, COUNT(ads_watched) AS ad_watched
    FROM adbreaks
    WHERE EXTRACT(WEEK FROM ts) = 1 AND EXTRACT(YEAR FROM ts) = 2017
    GROUP BY video_id
    ORDER BY ad_watched DESC
    LIMIT 10;

然后使用WHERE EXTRACT(WEEK FROM ts) = 2,3, and 4运行查询它将为您提供2017年1月的统计数据

如果您不关心这一年并希望累积所有可用数据，请删除年份约束

在mysql中：

SELECT video_id, COUNT(ads_watched) AS ad_watched
    FROM adbreaks
    WHERE WEEK(ts) = 1 AND YEAR(ts) = 2017
    GROUP BY video_id
    ORDER BY ad_watched DESC
    LIMIT 10;

MYSQL：每周返回生成最多广告的视频

1 个答案: