Question

在下表中，我不知道如何执行此操作，但如何编写为每个唯一的PhoneNumber返回最新行的查询？

PhoneNumber    MessageText               ReceiveTime        
-------------  ------------------------  -------------------
+639148186649  Delivery please           2013-03-19 01:12:55
+639148186649  I need this item          2013-03-22 02:15:01
+639148186649  I need more of this item  2013-03-23 12:01:02
+639194357455  How much for this...      2013-03-24 16:36:33
+639194357455  What time do you open?    2013-03-24 17:55:07

Answer 1

我找到了答案！

SELECT s1.PhoneNumber, s1.MessageText, s1.ReceiveTime FROM mytable s1 LEFT JOIN mytable s2
    ON (s1.PhoneNumber = s2.PhoneNumber AND s1.ReceiveTime < s2.ReceiveTime)
    WHERE s2.ReceiveTime IS NULL ORDER BY ReceiveTime DESC

Answer 2

您不能按一列分组并返回其他不依赖于该列的列。有关提示，请参阅this question的答案。

Answer 3

我认为这应该有用......

SELECT *
FROM PhoneTable
GROUP BY PhoneNumber
HAVING ReceiveTime = MAX(ReceiveTime)
ORDER BY ReceiveTime

..或者您可能需要做这样的事情......

SELECT PhoneNumber, MessageText, ReceiveTime
FROM PhoneTable t
WHERE ReceiveTime = (SELECT MAX(ReceiveTime)
                     FROM t
                     GROUP BY PhoneNumber
                     HAVING PhoneNumber = t.PhoneNumber)

MySQL：如何返回每个唯一编号的最新行

3 个答案: