Question

我正在研究银行家算法并使用循环来创建我的线程。问题是，当应该创建其中5个时，循环只创建4个线程。我已经检查了我的循环，除非我遗漏了一些东西，否则一切似乎都是正确的。

/* these may be any values >= 0 */

#define NUMBER_OF_CUSTOMERS 5
#define NUMBER_OF_RESOURCES 3

/* the available amount of each resource */
int available[NUMBER_OF_RESOURCES];

/*the maximum demand of each customer */
int maximum[NUMBER_OF_CUSTOMERS][NUMBER_OF_RESOURCES];

/* the amount currently allocated to each customer */
int allocation[NUMBER_OF_CUSTOMERS][NUMBER_OF_RESOURCES];

/* the remaining need of each customer */
int need[NUMBER_OF_CUSTOMERS][NUMBER_OF_RESOURCES];

int release_resources(int customer_num, int release[]){
   allocation[customer_num][NUMBER_OF_RESOURCES];
   return 1;
}

pthread_mutex_t mutex;

int main(int argc, char *argv[]){

  pthread_mutex_init(&mutex, NULL);

  pthread_t threads [3];
  int result;
  unsigned index;

  for(index = 0; index < NUMBER_OF_RESOURCES; index++){
    available[index] = strtol(argv[index+1], NULL,10);
  } 

  for(index = 0; index < NUMBER_OF_CUSTOMERS; ++index){
    printf("\nCreating thead %d", index);
    result = pthread_create(&threads[index],NULL,release_resources,1);  
  }

  //printf("Done");
  return 0;
}

Answer 1

如我所见，你的主要内容有一个错误：

int main(int argc, char *argv[]){

  //...

  pthread_t threads [3];
  int result;
  unsigned index;

  //... 

  for(index = 0; index < NUMBER_OF_CUSTOMERS; ++index){
    printf("\nCreating thead %d", index);
    result = pthread_create(&threads[index],NULL,release_resources,1);  
  }

  //...
  return 0;
}

在这种情况下，数组threads 的大小为3项，而您的索引来自for循环，的范围为0到4（大小为5项），记住你的常数#define NUMBER_OF_CUSTOMERS 5。我很惊讶你得到了4个线程，它应该在内存访问冲突之前创建3个。

您应该使用正确的大小重新定义数组线程，并使用常量NUMBER_OF_CUSTOMERS，如下：pthread_t threads [NUMBER_OF_CUSTOMERS];

在C中的for循环中创建多个pthread

1 个答案: