Question

我正在建立一个预订系统，我必须根据旺季/淡季等增加或减少价格。

这是Alessandro的一些好帮助后的最终功能:) 它现在无需在赛季阵列中使用一年。

    var seasonArray = [ 
        {
            "season": "HIGH Season",
            "from": 101,
            "to": 315,
            "pct": 30
        },
        {
            "season" : "MIDDLE Season",
            "from": 316,
            "to": 615,
            "pct" : 10
        },
        {
            "season" : "LOW Season",
            "from": 616,
            "to": 915,
            "pct" : -10
        }
    ]

    var checkin  = Date.parse('2017-01-01 00:00:00')
    var checkout = Date.parse('2017-09-05 00:00:00')

    calcPrice(checkin, checkout);

function calcPrice(checkin, checkout){
    var nights    = daysBetween(new Date(checkin), new Date(checkout))
    var totPrice  = calcPeriod(nights,checkin);
    var avgPrice  = Math.round(totPrice/nights);
    totPrice      = avgPrice * nights //compensate for math.round difference
    var finalPrice = 0;
    for (var d = new Date(checkin); d <= checkout; d.setDate(d.getDate() + 1)) {
        dn = Number((d.getMonth()+1) + ('0' + d.getDate()).slice(-2)) 
        var season = seasonArray.find(item => {
           return item.from <= dn && item.to >= dn
        });
        var pct = season ? season.pct : 0;
        finalPrice += avgPrice * (1 + pct / 100);
    }
    finalPrice = Math.round(finalPrice)
    console.log('totPrice: ' + totPrice)
    console.log('finalPrice: ' + finalPrice)
}

Answer 1

您可以使用以下方法：

创建一个带日期范围的seasonArray（您可以使用变量轻松更改我的示例中的当前年份）
从登记入住到结帐的每一天
最后使用find功能来获得正确的＆＃34;赛季＆＃34;用于调整最终价格

请参阅我的示例（可以改进）：

＆＃13;

var seasonArray = [{
  "season": "HIGH Season",
  "from": Date.parse('2017-01-01 00:00:00'),
  "to": Date.parse('2017-03-15 23:59:59'),
  "pct": 30
}, {
  "season": "MIDDLE Season",
  "from": Date.parse('2017-03-16 00:00:00'),
  "to": Date.parse('2017-06-15 23:59:59'),
  "pct": 10
}, {
  "season": "LOW Season",
  "from": Date.parse('2017-06-16 00:00:00'),
  "to": Date.parse('2017-09-15 23:59:59'),
  "pct": -10
}]

var checkin = Date.parse('2017-01-06 00:00:00');
var checkout = Date.parse('2017-05-18 00:00:00');

var days = (checkout / 1000 - checkin / 1000) / 86400; //seconds per day
var totPrice = 13200;
var avgPrice = totPrice / days;
var finalPrice = 0;

for (var d = new Date(checkin); d <= checkout; d.setDate(d.getDate() + 1)) {
    var season = seasonArray.find(item => {
       return item.from <= d && item.to >= d
    });
    var pct = season ? season.pct : 0;
    finalPrice += avgPrice * (1 + pct / 100);
}
console.log("Final price is: " + finalPrice);

＆＃13;

我希望它可以帮助你，再见

编辑：我在可能的npe上添加了一些检查

var pct = season？ season.pct：0;

以更智能的方式进行大量日期比较

1 个答案: