Question

我正在尝试为我的实验编写一个函数，该函数在中间的彩色矩形上方显示2个标签。受试者必须向左或向右按下以使用上述标签之一对颜色进行分类。

我想在循环中编码，如果精度= 1，那么实验应该显示一个信息文本说明他们的选择是正确的，反之亦然，如果准确度= 0.他们按Enter继续，它应该回到原始循环，然后重复自己。

我该怎么做？

# make a function for one trial of colour practice
def con1_trial(self):
    global trial
    global key
    trial += 1
    target_colour = random.choice(colours) 

    # show one square with gouloboy colour in top right corner of screen
    col3rec.setFillColor(target_colour)
    col3rec.draw()
    sinij_text.draw()
    boy_text.draw()

    # draw and flip
    win.flip()

    key, test_answer = event.waitKeys(keyList=['right', 'left', 'escape'], timeStamped = True)[0]
    for colour_pair in colour_pairs:
        if test_colour == colours[0] and key == "left":
            accuracy = 1
        elif test_colour == colours[1] and key == "right":
            accuracy = 1
        elif key == 'escape':
            core.quit() 
        else: accuracy = 0

    # records time in ms
    rt = (test_answer - test_start)*1000
    return accuracy, rt

Answer 1

试用版定义为选择颜色，绘图，等待输入，然后记录答案。这是一些伪代码

def trial():
    color = random.choice(colours)
    # draw stuff
    # set time start
    # wait for key press
    # check if key press correct
    # print whether they were correct and the time
    if enter pressed: trial()

Answer 2

为了使代码整洁，首先在脚本中的某个位置定义反馈函数：

feedback_text = visual.TextStim(win)
def show_feedback(feedback):
    # Show feedback on screen
    feedback_text.text = feedback
    feedback_text.draw()
    win.flip()

    # Wait for key
    event.waitKeys()

按照您的代码添加以下内容：

# Show feedback
if accuracy == 1:
    show_feedback('Correct! Well done. Press a key to continue...')
elif accuracy == 0:
    show_feedback('Wrong! Press a key to continue...')

...具有正确的缩进级别。我总是最终有某种功能来显示信息。在show_feedback中，您还可以添加一些内容以退出实验：

key = event.waitKeys()[0]  # get first key pressed
if key == 'escape':
    core.quit()

如何检查循环内的准确性？

2 个答案: