我想使用nsolve作为solve的后备，并希望使用dict = True使solve返回包含找到的解决方案和相应变量的字典。但是，nsolve似乎没有此选项。
这就是我使用的解决方法：
from sympy import *
def nsolve(equations, variables, guesses, **flags):
from sympy import nsolve as originalnsolve
result = originalnsolve(equations, variables, guesses, **flags)
if "dict" in flags and flags["dict"]:
return [dict(zip(variables, [float(value) for value in result]))]
else:
return result
x, y = symbols("x y")
equations = [Eq(2*x+y, 3), Eq(y-x, 1)]
variables = [x, y]
guesses = [1, 1]
print("solve with dict = True produces:\n%s\n" % solve(equations, variables, dict = True) + "The result is a dictionary, as needed\n")
print("nsolve without dict = True produces:\n%s\n" % nsolve(equations, variables, guesses) + "nsolve doesn't return a dictionary\n")
print("nsolve with dict = True produces:\n%s\n" % nsolve(equations, variables, guesses, dict = True) + "My workaround wrapper function returns a dictionary\n")
输出结果为：
solve with dict = True produces:
[{x: 2/3, y: 5/3}]
The result is a dictionary, as needed
nsolve without dict = True produces:
[0.666666666666667]
[ 1.66666666666667]
nsolve doesn't return a dictionary
nsolve with dict = True produces:
[{x: 0.6666666666666666, y: 1.6666666666666667}]
My workaround wrapper function returns a dictionary
我的问题：
我错过了一个简单的方法让nsolve返回字典吗？
如果没有：我的做法有问题吗？