我想创建一个包含1 1 1 2 2 2 3 3 3 4 4 4 5 5 5的列...一直到500 500 500.我被告知尝试使用generate_series，但还没有能够找到解决方案。
答案 0 :(得分：1)
由于@FormUrlEncoded
@POST(GlobalVariables.LOGIN_URL)
void Login(@Field("email") String key, @Field("password") String value, Callback<Response> callback);
getService().Login(email, password, new MyCallback<Response>(context, true, null)
{
@Override
public void failure(RetrofitError arg0)
{
// TODO Auto-generated method stub
UtilitySingleton.dismissDialog((BaseActivity<?>) context);
System.out.println(arg0.getResponse());
}
@Override
public void success(Response arg0, Response arg1)
{
String result = null;
StringBuilder sb = null;
InputStream is = null;
try
{
is = arg1.getBody().in();
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
result = sb.toString();
System.out.println("Result :: " + result);
}
}
catch (Exception e)
{
e.printStackTrace();
}
}
});
generate_series()第一次调用select i
from generate_series(1,500) as t(i)
cross join generate_series(1,3)
order by i;
会生成1到500之间的数字，然后交叉连接会使每行三倍。