如何使用OpenCV删除小的连接对象

Question

我使用OpenCV和Python，我想从我的图像中删除小的连接对象。

我有以下二进制图像作为输入：

图像是此代码的结果：

dilation = cv2.dilate(dst,kernel,iterations = 2)
erosion = cv2.erode(dilation,kernel,iterations = 3)

我想删除以红色突出显示的对象：

如何使用OpenCV实现这一目标？

Answer 1

connectedComponentsWithStats：

怎么样？

#find all your connected components (white blobs in your image)
nb_components, output, stats, centroids = cv2.connectedComponentsWithStats(img, connectivity=8)
#connectedComponentswithStats yields every seperated component with information on each of them, such as size
#the following part is just taking out the background which is also considered a component, but most of the time we don't want that.
sizes = stats[1:, -1]; nb_components = nb_components - 1

# minimum size of particles we want to keep (number of pixels)
#here, it's a fixed value, but you can set it as you want, eg the mean of the sizes or whatever
min_size = 150  

#your answer image
img2 = np.zeros((output.shape))
#for every component in the image, you keep it only if it's above min_size
for i in range(0, nb_components):
    if sizes[i] >= min_size:
        img2[output == i + 1] = 255

输出：

Answer 2

要自动删除对象，您需要在图像中找到它们。 从您提供的图像中我看不到任何区别7个突出显示的项目与其他项目。 您必须告诉计算机如何识别您不想要的对象。如果它们看起来一样，那是不可能的。

如果您有多个图像，其中对象总是看起来像您可以使用模板匹配技术。

关闭操作对我来说也没什么意义。