Question

可能是一个简单的问题。

我有data.frame（样本名称，因子级别和因子级别的复制品）：

df <- data.frame(name=c("DP_A","DP_B","PA_A","PA_B","PA_C"),
                 level=c("DP","DP","PA","PA","PA"),
                 replicate=c("A","B","A","B","C"),
                 stringsAsFactors = F)

以及其列之一的给定所需顺序 - 因子级别：

level.order <- c("PA","DP")

所以我想按df（意为level.order）订购df$level。

如果我可以加入level.order我可以按df$replicate订购，可以是character（如本例所示），integer，或它们的组合（例如，A1，A2等）

在这种情况下，有序的df将是：

df <- data.frame(name=c("PA_A","PA_B","PA_C","DP_A","DP_B"),
                 level=c("PA","PA","PA","DP","DP"),
                 replicate=c("A","B","C","A","B"),
                 stringsAsFactors = F)

Answer 1

有几种选择。一个是a [589, 273, 981, 642, 702, 883, 319, 128] b [(589, 0), (273, 1), (981, 2), (642, 3), (702, 4), (883, 5), (319, 6), (128, 7)] c [(128, 7), (273, 1), (319, 6), (589, 0), (642, 3), (702, 4), (883, 5), (981, 2)] d [7, 1, 6, 0, 3, 4, 5, 2] z [128, 273, 319, 589, 642, 702, 883, 981] y <zip object at 0x035E38A0> x [(7, 128), (1, 273), (6, 319), (0, 589), (3, 642), (4, 702), (5, 883), (2, 981)] w [(0, 589), (1, 273), (2, 981), (3, 642), (4, 702), (5, 883), (6, 319), (7, 128)] v [589, 273, 981, 642, 702, 883, 319, 128] u [589, 273, 981, 642, 702, 883, 319, 128]'级别'列，基于它match order`

level.order' to get the numeric index and then

或将“级别”转换为df[order(match(df$level, level.order)),]，将factor指定为“level.order”，然后将levels指定为<{p}}

order

根据给定的订单订购数据框

1 个答案: