c#中是否有一种方法可以遍历类的属性?
基本上我有一个包含大量属性的类(它基本上包含大型数据库查询的结果)。 我需要将这些结果作为CSV文件输出,因此需要将每个值附加到字符串中。
显然可以手动将每个值附加到字符串,但有没有办法有效地循环结果对象并依次为每个属性添加值?
答案 0 :(得分:48)
不确定;你可以通过多种方式做到这一点;从反思开始(注意,这很慢 - 虽然适用于适量的数据):
var props = objectType.GetProperties();
foreach(object obj in data) {
foreach(var prop in props) {
object value = prop.GetValue(obj, null); // against prop.Name
}
}
然而;对于更大量的数据,值得提高效率;例如,我在这里使用Expression
API来预编译一个看起来写入每个属性的委托 - 这里的优点是不会对每行进行反映(对于大量数据,这应该明显更快) ):
static void Main()
{
var data = new[] {
new { Foo = 123, Bar = "abc" },
new { Foo = 456, Bar = "def" },
new { Foo = 789, Bar = "ghi" },
};
string s = Write(data);
}
static Expression StringBuilderAppend(Expression instance, Expression arg)
{
var method = typeof(StringBuilder).GetMethod("Append", new Type[] { arg.Type });
return Expression.Call(instance, method, arg);
}
static string Write<T>(IEnumerable<T> data)
{
var props = typeof(T).GetProperties();
var sb = Expression.Parameter(typeof(StringBuilder));
var obj = Expression.Parameter(typeof(T));
Expression body = sb;
foreach(var prop in props) {
body = StringBuilderAppend(body, Expression.Property(obj, prop));
body = StringBuilderAppend(body, Expression.Constant("="));
body = StringBuilderAppend(body, Expression.Constant(prop.Name));
body = StringBuilderAppend(body, Expression.Constant("; "));
}
body = Expression.Call(body, "AppendLine", Type.EmptyTypes);
var lambda = Expression.Lambda<Func<StringBuilder, T, StringBuilder>>(body, sb, obj);
var func = lambda.Compile();
var result = new StringBuilder();
foreach (T row in data)
{
func(result, row);
}
return result.ToString();
}
答案 1 :(得分:18)
foreach (PropertyInfo prop in typeof(MyType).GetProperties())
{
Console.WriteLine(prop.Name);
}
答案 2 :(得分:5)
我在这个页面上尝试了各种推荐,但我无法让它们起作用。我从最顶层的答案开始(你会注意到我的变量同样被命名),并且我自己完成了它。这就是我的工作 - 希望它可以帮助别人。
var prop = emp.GetType().GetProperties(); //emp is my class
foreach (var props in prop)
{
var variable = props.GetMethod;
empHolder.Add(variable.Invoke(emp, null).ToString()); //empHolder = ArrayList
}
***我应该提到这只会在你使用get; set; (公共)财产。
答案 3 :(得分:3)
您可以列出对象的属性
IList<PropertyInfo> properties = typeof(T).GetProperties().ToList();
然后使用foreach导航到列表中..
foreach (var property in properties)
{
here's code...
}
答案 4 :(得分:1)
使用类似
的内容StringBuilder csv = String.Empty;
PropertyInfo[] ps this.GetType().GetProperties();
foreach (PropertyInfo p in ps)
{
csv.Append(p.GetValue(this, null);
csv.Append(",");
}
答案 5 :(得分:1)
var csv = string.Join(",",myObj
.GetType()
.GetProperties(BindingFlags.Public | BindingFlags.Instance)
.Select(p => p.GetValue(myObj, null).ToString())
.ToArray());
答案 6 :(得分:0)
这是如何遍历vb.net中的属性,它在c#中的概念相同,只是翻译语法:
Dim properties() As PropertyInfo = Me.GetType.GetProperties(BindingFlags.Public Or BindingFlags.Instance)
If properties IsNot Nothing AndAlso properties.Length > 0 Then
properties = properties.Except(baseProperties)
For Each p As PropertyInfo In properties
If p.Name <> "" Then
p.SetValue(Me, Date.Now, Nothing) 'user p.GetValue in your case
End If
Next
End If
答案 7 :(得分:0)
循环使用属性
Type t = typeof(MyClass);
foreach (var property in t.GetProperties())
{
}
答案 8 :(得分:0)
string target = "RECEIPT_FOOTER_MESSAGE_LINE" + index + "Column";
PropertyInfo prop = xEdipV2Dataset.ReceiptDataInfo.GetType().GetProperty(target);
Type t = xEdipV2Dataset.ReceiptDataInfo.RECEIPT_FOOTER_MESSAGE_LINE10Column.GetType();
prop.SetValue(t, fline, null);
内容:目标对象必须是可以选择的
答案 9 :(得分:0)
string notes = "";
Type typModelCls = trans.GetType(); //trans is the object name
foreach (PropertyInfo prop in typModelCls.GetProperties())
{
notes = notes + prop.Name + " : " + prop.GetValue(trans, null) + ",";
}
notes = notes.Substring(0, notes.Length - 1);
然后我们可以将notes字符串作为列写入日志表或文件。您必须使用System.Reflection来使用PropertyInfo
答案 10 :(得分:0)
从简单的类对象获取属性值....
class Person
{
public string Name { get; set; }
public string Surname { get; set; }
public int Age { get; set; }
}
class Program
{
static void Main(string[] args)
{
var person1 = new Person
{
Name = "John",
Surname = "Doe",
Age = 47
};
var props = typeof(Person).GetProperties();
int counter = 0;
while (counter != props.Count())
{
Console.WriteLine(props.ElementAt(counter).GetValue(person1, null));
counter++;
}
}
}