Question

我必须从下面的表格中找到每周平均值（仅限工作日 - 星期一至星期五）。我正在搜索的平均值是AVAI_NUM。我必须计算给定时期内每周AVAI_NUM的平均值。

实施例：如果期限是2016年1月：

declare @dDateFrom date = cast('2016-01-01' as date)
declare @dDateTo date = cast('2016-01-31' as date)

表格如下：

declare @scavai table
(
    avai_key int,
    avai_dat date,
    avai_num int
)

用数据填写表格：

insert into @scavai(avai_Key, avai_dat, avai_num)
    select 1, cast('2016-01-01' as date), 3
    union all
    select 1, cast('2016-01-02' as date), 2
    union all
    select 1, cast('2016-01-03' as date), 5
    union all
    select 1, cast('2016-01-04' as date), 6
    union all
    select 1, cast('2016-01-05' as date), 1
    union all
    select 1, cast('2016-01-06' as date), 8
    union all
    select 1, cast('2016-01-07' as date), 4
    union all
    select 1, cast('2016-01-08' as date), 3
    union all
    select 1, cast('2016-01-09' as date), 2
    union all
    select 1, cast('2016-01-10' as date), 1
    union all
    select 1, cast('2016-01-11' as date), 9
    union all
    select 1, cast('2016-01-12' as date), 7
    union all
    select 1, cast('2016-01-13' as date), 3
    union all
    select 1, cast('2016-01-14' as date), 8
    union all
    select 1, cast('2016-01-15' as date), 3
    union all
    select 1, cast('2016-01-16' as date), 2
    union all
    select 1, cast('2016-01-17' as date), 3
    union all
    select 1, cast('2016-01-18' as date), 1
    union all
    select 1, cast('2016-01-19' as date), 4
    union all
    select 1, cast('2016-01-20' as date), 5
    union all
    select 1, cast('2016-01-21' as date), 7
    union all
    select 1, cast('2016-01-22' as date), 3
    union all
    select 1, cast('2016-01-23' as date), 3
    union all
    select 1, cast('2016-01-25' as date), 3
    union all
    select 1, cast('2016-01-26' as date), 3

我知道如何计算给定时期内的周数：

select DATEDIFF(ww, '2016-01-01', '2016-01-31')

但我不知道如何计算每周工作日的AVAI_NUM，并将其除以特定周的天数，然后总结所有这些并除以周数？

Answer 1

试，

select *,
    AVG(cast(avai_num as decimal)) over 
    (partition by datepart(week,  avai_dat) order by (select 1)) avg1
    from @scavai 
    where avai_dat between @dDateFrom and @dDateTo 
    order by avai_dat

获取每周工作日的每周平均值

1 个答案: