Question

我拥有的：每个产品每日营业额的表格。

我需要什么：提取当周平均每日营业额大于去年（52周）平均每周营业额的产品名称和价值。

不幸的是，oracle说单行子查询返回多行，我不知道我做错了什么。

SELECT NAME, AVG(TURNOVER)/52
FROM DAILY_STATS
WHERE TYPE=243 AND T_DATE >= SYSDATE - 365
GROUP BY NAME
HAVING AVG(TURNOVER)/52 > 0 
AND 
AVG(TURNOVER) > 
(SELECT AVG(TURNOVER)
FROM DAILY_STATS
WHERE TYPE=243 AND T_DATE >= TO_DATE(TRUNC(sysdate, 'DAY'),'DD/MM/YYYY')
GROUP BY NAME);

Answer 1

SELECT AVG(TURNOVER)
FROM DAILY_STATS
WHERE TYPE=243 AND T_DATE >= TO_DATE(TRUNC(sysdate, 'DAY'),'DD/MM/YYYY')
GROUP BY NAME

您的子查询返回多个值。

AVG(TURNOVER) >此处>运算符是标量运算符，只能比较一个值。

可能的解决方案

AVG(TURNOVER) > all
(SELECT AVG(TURNOVER)
FROM DAILY_STATS
WHERE TYPE=243 AND T_DATE >= TO_DATE(TRUNC(sysdate, 'DAY'),'DD/MM/YYYY')
GROUP BY NAME);

OR

AVG(TURNOVER) > ANY
(SELECT AVG(TURNOVER)
FROM DAILY_STATS
WHERE TYPE=243 AND T_DATE >= TO_DATE(TRUNC(sysdate, 'DAY'),'DD/MM/YYYY')
GROUP BY NAME);

运算符> ANY和> all将标量运算符转换为多行运算符。请注意，这可能符合您的逻辑，也可能不符合您的逻辑。

编辑：回答太早了。现在纠正。

EDIT2：

从语法上讲，查询获取结果，但是Frank提到你的逻辑似乎有点偏离

表格内容

+------+----------+------+-----------+
| NAME | TURNOVER | TYPE |  T_DATE   |
+------+----------+------+-----------+
| ABC  |      100 |    2 | 03-MAY-16 |
| ABD  |      200 |    2 | 02-MAY-16 |
| ABE  |      300 |    2 | 01-MAY-16 |
| ABF  |      400 |    2 | 30-APR-16 |
| ABF  |      500 |    2 | 29-APR-16 |
| ABG  |      600 |    2 | 28-APR-16 |
| ABH  |      700 |    3 | 27-APR-16 |
| ABH  |      800 |    2 | 28-APR-16 |
| ABH  |      900 |    2 | 28-APR-16 |
| ABH  |     1900 |    2 | 28-APR-16 |
| ABH  |     2900 |    2 | 28-APR-16 |
| ABH  |     3900 |    2 | 28-APR-16 |
| ABH  |   113900 |    2 | 28-APR-16 |
| ABH  |  1213900 |    2 | 28-APR-16 |
+------+----------+------+-----------+

<强>查询

SELECT NAME, AVG(TURNOVER)/52
FROM DAILY_STATS
WHERE TYPE=2 AND T_DATE >= SYSDATE - 365
GROUP BY NAME
HAVING AVG(TURNOVER)/52 > 0 
AND 
AVG(TURNOVER) > any
(SELECT AVG(TURNOVER)
FROM DAILY_STATS
WHERE TYPE=2 AND T_DATE >= sysdate-7
GROUP BY NAME);

<强> RESULT

+------+-------------------------------------------+
| NAME |             AVG(TURNOVER)/52              |
+------+-------------------------------------------+
| ABG  | 11.53846153846153846153846153846153846154 |
| ABD  | 3.84615384615384615384615384615384615385  |
| ABE  | 5.76923076923076923076923076923076923077  |
| ABF  | 8.65384615384615384615384615384615384615  |
| ABH  | 3676.373626373626373626373626373626373627 |
+------+-------------------------------------------+

Answer 2

您没有正确过滤标量子查询的输入数据 - 因为您想要比较同一产品的平均值，您需要按产品名称进行过滤：

with daily_stats(type, t_date, turnover, name) as (
  select 243, date '2016-01-01', 200, 'P' from dual union all
  select 243, date '2016-05-04', 300, 'P' from dual union all
  select 243, date '2016-01-01', 200, 'Q' from dual)   
SELECT NAME, AVG(TURNOVER)/52
  FROM DAILY_STATS ds1
 WHERE TYPE=243 AND T_DATE >= SYSDATE - 365
GROUP BY NAME
HAVING AVG(TURNOVER)/52 > 0 
AND 
AVG(ds1.TURNOVER) <
(SELECT AVG(ds2.TURNOVER)
 FROM DAILY_STATS ds2
 WHERE ds2.TYPE=243 AND ds2.T_DATE >= TO_DATE(TRUNC(sysdate, 'DAY'),'DD/MM/YYYY')
 and ds2.name = ds1.name);

这将解析您的＆＃34;单行子查询......＆＃34;错误。但是，我并非100％确定您的逻辑是合理的 - 您是否真的想将每日平均值与每周（即超过7天）进行比较？

Oracle SQL - 本周的平均营业额高于去年的平均每周营业额

2 个答案: