Question

我使用try catch块处理了Jenkins管道步骤。我想在某些情况下手动抛出异常。但它显示以下错误。

org.jenkinsci.plugins.scriptsecurity.sandbox.RejectedAccessException: Scripts not permitted to use new java.io.IOException java.lang.String

我查看了scriptApproval部分，并且没有待批准。

Answer 1

如果要在异常时中止程序，可以使用管道步骤error来阻止管道执行并出现错误。示例：

try {
  // Some pipeline code
} catch(Exception e) {
   // Do something with the exception 

   error "Program failed, please read logs..."
}

如果你想以成功状态停止你的管道，你可能想要某种布尔值，表明你的管道必须停止，例如：

boolean continuePipeline = true
try {
  // Some pipeline code
} catch(Exception e) {
   // Do something with the exception 

   continuePipeline = false
   currentBuild.result = 'SUCCESS'
}

if(continuePipeline) {
   // The normal end of your pipeline if exception is not caught. 
}

Answer 2

这就是我在Jenkins 2.x中的做法。

注意：不要使用错误信号，它会跳过任何发布步骤。

stage('stage name') {
            steps {
                script {
                    def status = someFunc() 

                    if (status != 0) {
                        // Use SUCCESS FAILURE or ABORTED
                        currentBuild.result = "FAILURE"
                        throw new Exception("Throw to stop pipeline")
                        // do not use the following, as it does not trigger post steps (i.e. the failure step)
                        // error "your reason here"

                    }
                }
            }
            post {
                success {
                    script {
                        echo "success"
                    }
                }
                failure {
                    script {
                        echo "failure"
                    }
                }
            }            
        }

Answer 3

似乎无法抛出Exception以外的其他类型的异常。没有IOException，没有RuntimeException等

这将起作用：

throw new Exception("Something went wrong!")

但是这些不会：

throw new IOException("Something went wrong!")
throw new RuntimeException("Something went wrong!")

Answer 4

我使用了.jenkinsfile。我是通过以下方式完成的：

    stage('sample') {
        steps {
            script{
                try{
                    bat '''sample.cmd'''
                    RUN_SAMPLE_RESULT="SUCCESS"
                    echo "Intermediate build result: ${currentBuild.result}"
                }//try
                catch(e){
                    RUN_SAMPLE_RESULT="FAILURE"
                    echo "Intermediate build result: ${currentBuild.result}"
                    // normal error handling
                    throw e
                }//catch
            }//script
        }//steps
    }//stage

基于RUN_SAMPLE_RESULT值，您可以设计生成后的操作。

如何在jenkins管道中抛出异常？

4 个答案: