ElasticSearch:TypeError:期望的字符串还是缓冲区?

时间:2017-03-10 09:08:47

标签: python json python-2.7 elasticsearch kibana

我编写了一个简单的python脚本来将JSON文件放到Elasticsearch.I想要根据我从JSON文件中提取的id字段来存储它。 但是当我尝试插入弹性搜索时,它会引发错误TypeError: expected string or buffer

以下是我正在处理的代码......

#! /usr/bin/python

import requests
from elasticsearch import Elasticsearch
import json
es = Elasticsearch([{'host':'localhost','port':9200}])
r = requests.get('http://127.0.0.1:9200')
i = 1
if r.status_code == 200:

        with open('d1.json') as json_data:
                d = json.load(json_data)

                for i in d['tc'][0]['i]['f']['h']:
                        if i['name'] == 'm':
                                m = i['value']
                                dope=str(m)
                                print dope
                                print type(dope)
                                #print type(md5)
                                es.index(index='lab', doc_type='report',id=dope,body=json.loads(json_data))

错误日志:

44d88612fea8a8f36de82e1278abb02f
<type 'str'>
Traceback (most recent call last):
  File "elastic_insert.py", line 22, in <module>
    es.index(index='labs', doc_type='report',id=dope,body=json.loads(json_data))
  File "/usr/lib/python2.7/json/__init__.py", line 339, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 364, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
TypeError: expected string or buffer

有关如何解决此错误的任何建议。我甚至尝试将m转换为int,但它又出现了另一个错误。

int(m)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '44d88612fea8a8f36de82e1278abb02f'

P.S:ElasticSearch服务已启动并正在运行。

1 个答案:

答案 0 :(得分:2)

问题与id无关。问题在于 &#34; json_data&#34 ;.它是一个文件流,因此您需要在es.index

中使用json.load而不是json.loads