Question

我已经发了一些相同错误的相关帖子，我已经尝试了几乎所有建议的解决方案。

以下是SQL：

SELECT Sum(h.counter1 + l.counter2) AS hour_amount 
FROM   ( 
          SELECT 1 
          FROM   xp_hour h 
          WHERE  h.account_id = '1' 
          AND    h.hour_date = Date('2017-03-06') 
          AND    (( 
                               h.from_time < Time('06:00') 
                        AND    h.till_time > Time('06:00')) 
                 OR     ( 
                               h.from_time < Time('15:00') 
                        AND    h.till_time > Time('15:00')) 
                 OR     ( 
                               h.from_time = Time('06:00') 
                        AND    h.till_time = Time('15:00')))) 
UNION ALL 
      ( 
             SELECT 1 
             FROM   xp_leave l 
             WHERE  l.account_id = '1' 
             AND    (( 
                                  l.from_datetime < Timestamp('2017-03-06 06:00') 
                           AND    l.till_datetime > Timestamp('2017-03-06 06:00')) 
                    OR     ( 
                                  l.from_datetime < Timestamp('2017-03-06 15:00') 
                           AND    l.till_datetime > Timestamp('2017-03-06 15:00')))) t_union

错误

Error: Every derived table must have its own alias

Answer 1

试试这个：

SELECT SUM(h.counter1 + l.counter2) AS hour_amount 
FROM (   
   SELECT 1 
   FROM xp_hour h 
   WHERE h.account_id = '1' AND h.hour_date = DATE('2017-03-06') AND 
         ( 
          (h.from_time < TIME('06:00') AND h.till_time > TIME('06:00')) OR 
          (h.from_time < TIME('15:00') AND h.till_time > TIME('15:00')) OR 
          (h.from_time = TIME('06:00') AND h.till_time = TIME('15:00'))
         )

   UNION ALL 

   SELECT 1 
   FROM xp_leave l 
   WHERE l.account_id = '1' AND 
       (
         (l.from_datetime < TIMESTAMP('2017-03-06 06:00') AND 
          l.till_datetime > TIMESTAMP('2017-03-06 06:00')) OR 
        (l.from_datetime < TIMESTAMP('2017-03-06 15:00') AND 
         l.till_datetime > TIMESTAMP('2017-03-06 15:00'))
       )
) t_union

您需要将整个 UNION ALL子查询括在括号中，而不是参与UNION ALL操作的各个子查询。

Answer 2

问题在于括号。第一个查询被解释为单独的问题，属于第一个。

试试这个：

SELECT SUM(h.counter1 + l.counter2) AS hour_amount FROM 
(SELECT 1 FROM xp_hour h WHERE h.account_id = '1' AND h.hour_date = DATE('2017-03-06') AND ((h.from_time < TIME('06:00') AND h.till_time > TIME('06:00')) OR (h.from_time < TIME('15:00') AND h.till_time > TIME('15:00')) OR (h.from_time = TIME('06:00') AND h.till_time = TIME('15:00'))) 
UNION ALL 
(SELECT 1 FROM xp_leave l WHERE l.account_id = '1' AND ((l.from_datetime < TIMESTAMP('2017-03-06 06:00') AND l.till_datetime > TIMESTAMP('2017-03-06 06:00')) OR (l.from_datetime < TIMESTAMP('2017-03-06 15:00') AND l.till_datetime > TIMESTAMP('2017-03-06 15:00'))))) t_union

我从第一个查询中删除了最后一个)到union

的结尾

Answer 3

在UNION ALL之前为派生表的第一部分命名别名，就像你为第二部分放置t_union一样。

例如：

(SELECT 1 
FROM xp_hour h 
WHERE h.account_id = '1' 
AND h.hour_date = DATE('2017-03-06') 
AND ((h.from_time < TIME('06:00') 
AND h.till_time > TIME('06:00')) 
OR (h.from_time < TIME('15:00') 
AND h.till_time > TIME('15:00')) 
OR (h.from_time = TIME('06:00') 
AND h.till_time = TIME('15:00')))) as t_union_1

Union SUM SQL必须有自己的别名

3 个答案: