我对这种奇怪的MySQL行为感到有些困惑。我收到了可怕的Every derived table must have its own alias
错误。
通常,我可以通过在主AS
语句中添加SELECT
子句来避免这种情况,但是它看起来不适用于以下示例:
SELECT SUM (`a`.`total`) AS `total` FROM (
SELECT COUNT(DISTINCT(`item_sales`.`id`)) AS `total`,
(SELECT COUNT(DISTINCT(`sale_item`)) AS `offers` FROM `item_sales_bids` WHERE `user_id` = 2) AS `offers`
FROM `item_sales`
INNER JOIN `item_sales_bids` ON `item_sales`.`id` = `item_sales_bids`.`sale_item`
WHERE `item_sales`.`buyer` != 2
AND `item_sales`.`sold` = 1
GROUP BY `item_sales`.`id`
HAVING `offers` > 0
) UNION (
SELECT COUNT(*) AS `total`,
`item_sales`.`reserve`,
(SELECT COUNT(*) FROM `item_sales_bids` WHERE `user_id` = 2) AS `bids`,
(SELECT MAX(`max_bid`) AS `max` FROM `item_sales_bids` WHERE `user_id` = 2) AS `maxBid`,
SUM((`item_sales`.`list_date` + (`item_sales`.duration * 86400)) - UNIX_TIMESTAMP()) AS `endTime`
FROM `item_sales`
INNER JOIN `item_sales_bids` ON `item_sales_bids`.`sale_item` = `item_sales`.`id`
GROUP BY `item_sales`.`id`
HAVING `endTime` < 0
AND `maxBid` < `item_sales`.`reserve`
)
) `a`
有谁可以指出我错过了什么?请注意,为连接添加别名会导致相同的错误。
答案 0 :(得分:4)
您应该在子查询中放置UNION
关键字,如下所示
SELECT SUM (`a`.`total`) AS `total`
FROM (
SELECT COUNT(DISTINCT(`item_sales`.`id`)) AS `total`,
(SELECT COUNT(DISTINCT(`sale_item`)) AS `offers` FROM `item_sales_bids` WHERE `user_id` = 2) AS `offers`
FROM `item_sales`
INNER JOIN `item_sales_bids` ON `item_sales`.`id` = `item_sales_bids`.`sale_item`
WHERE `item_sales`.`buyer` != 2
AND `item_sales`.`sold` = 1
GROUP BY `item_sales`.`id`
HAVING `offers` > 0
UNION
SELECT COUNT(*) AS `total`,
`item_sales`.`reserve`,
(SELECT COUNT(*) FROM `item_sales_bids` WHERE `user_id` = 2) AS `bids`,
(SELECT MAX(`max_bid`) AS `max` FROM `item_sales_bids` WHERE `user_id` = 2) AS `maxBid`,
SUM((`item_sales`.`list_date` + (`item_sales`.duration * 86400)) - UNIX_TIMESTAMP()) AS `endTime`
FROM `item_sales`
INNER JOIN `item_sales_bids` ON `item_sales_bids`.`sale_item` = `item_sales`.`id`
GROUP BY `item_sales`.`id`
HAVING `endTime` < 0
AND `maxBid` < `item_sales`.`reserve`
) `a`
答案 1 :(得分:1)
您可以在子查询中包含UNION
,
SELECT SUM (`a`.`total`) AS `total`
FROM
(
--- your first query
UNION
--- your second query
) a