我有2张桌子
表1
id product
1 P1
2 P2
表2
id amount product_t1
1 100 P1
2 200 P1
3 300 P2
4 400 P1
5 500 P2
我希望我的输出为:
product totalAmount(sum of amount)
P1 700
P2 800
编辑:到目前为止,这是我的查询
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
谢谢!
答案 0 :(得分:1)
由于您没有使用外键,因此您甚至不需要表1 来获得所需的结果。
np.load(open('file.npy'))
您缺少的是SELECT
product_t1 AS product,
SUM(amount) AS totalAmount
FROM table2
GROUP BY product_t1
声明,以便为每个产品单独添加一行
答案 1 :(得分:1)
你应该使用group by
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
GROUP BY product
答案 2 :(得分:1)
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
GROUP BY product T1.product
使用GROUP BY
标记。 Group by有助于根据产品价值对结果进行分组
答案 3 :(得分:0)
尝试使用function display_graph(id, label, data) {
var ctx = document.getElementById(id);
var data = {
labels: data.labels,
datasets: [
{
label: label,
fill: false,
lineTension: 0.1,
backgroundColor: "rgba(75,192,192,0.4)",
borderColor: "rgba(75,192,192,1)",
borderCapStyle: 'butt',
borderDash: [],
borderDashOffset: 0.0,
borderWidth: 1,
borderJoinStyle: 'miter',
pointBorderColor: "rgba(75,192,192,1)",
pointBackgroundColor: "#fff",
pointBorderWidth: 1,
pointHoverRadius: 5,
pointHoverBackgroundColor: "rgba(75,192,192,1)",
pointHoverBorderColor: "rgba(220,220,220,1)",
pointHoverBorderWidth: 2,
pointRadius: 1,
pointHitRadius: 10,
data: data.assay_value,
spanGaps: false
}
]
};
//options
var options = {
responsive: true,
title: {
display: true,
position: "top",
text: label,
fontSize: 18,
fontColor: "#111"
},
legend: {
display: true,
position: "bottom",
labels: {
fontColor: "#333",
fontSize: 16
}
}
};
var Blanks_Chart=null;
Blanks_Chart = new Chart(ctx, {
type: 'line',
data: data,
options: options
});}
和GROUP BY
AS
https://dev.mysql.com/doc/refman/5.7/en/group-by-modifiers.html
或者
添加到您的代码组 SELECT product_t1 as product, SUM(amount) AS totalAmount FROM table2
GROUP BY product