Question

我有以下SQL代码：

select user_id, quest_registration.quest_id, count(quest.quest_id), quest.quest_rarity, 
       case quest.quest_rarity 
       when 1 then count(user_id) * 1 
       when 2 then count(user_id) * 2 
       when 3 then count(user_id) * 3 
       when 4 then count(user_id) * 4 
       when 5 then count(user_id) * 5 
       end as points, 
       SUM(points)
from quest_registration 
inner join quest 
on quest_registration.quest_id = quest.quest_id
where user_id=2 AND quest_registration.date_completed is not null
group by quest.quest_rarity;

我想显示点总和列。我该怎么做？

解决新问题

我有以下创建功能：


CREATE FUNCTION points_earned (u_id INT)
RETURNS INT
BEGIN
    DECLARE cnt1 INT DEFAULT 0;
    select SUM(points)
    from (select case quest.quest_rarity 
            when 1 then count(user_id) * 1 
            when 2 then count(user_id) * 2 
            when 3 then count(user_id) * 3 
            when 4 then count(user_id) * 4 
            when 5 then count(user_id) * 5 
        end as points
        from quest_registration inner join quest 
        on quest_registration.quest_id=quest.quest_id
        where user_id=2 AND quest_registration.date_completed is not null
        group by quest.quest_rarity) x;

RETURN cnt1;


END $$

这个创建函数代码给出了一个错误：第3行的ERROR 1415（0A000）：不允许从函数返回结果集

这是什么意思？

另一列MySQL的总和

0 个答案: