Question

describe "Team::Membership" do
  let(:team) { Team.last }
  let(:user) { User.last }
  let(:membership) {user.apply_for(team)}

  it "can be rejected" do
    assert_difference "team.denied_applications.reload.count", +1 do
      assert_difference "team.applications.reload.count", -1 do
        assert_difference "team.members.reload.count", 0 do
          membership.reject!
        end
      end
    end
    membership.state.must_equal "denied"
  end

如果申请被拒绝，则范围denied_applications增加1，applications为-1，members根本不会改变。

# team.rb
  has_many :memberships, dependent: :destroy
  has_many :members, -> { where(team_memberships: {state: :confirmed}) }, through: :memberships, source: :user
  has_many :ex_members, -> { where(team_memberships: {state: :left}) }, through: :memberships, source: :user
  has_many :applications, -> { where(state: :pending) }, class_name: "Membership"
  has_many :denied_applications, -> { where(state: :denied) }, class_name: "Membership"

所以我的问题更有可能：这是一个很好的写作测试还是你会写的

team.denied_applications.reload.count.must_equal(1)
team.applications.reload.count.must_equal(0)
team.members.reload.count.must_equal(0)

Answer 1

有些人会争辩说差异断言应该在不同的测试中，但恕我直言，在这种情况下这不是问题。

在我看来，最重要的是你正在打电话

let(:team) { Team.last }
let(:user) { User.last }

为了确保您的测试不依赖于彼此或相互干扰，应该在测试运行之间清理数据库，因此如果这样做，您可以编写如下内容：

let(:team) { Team.create }
let(:user) { User.create }

或者您可以使用类似factory_girl之类的内容来更轻松地创建记录，例如，如果您正在进行某些验证并且不想在任何地方输入有效数据。

这是一个很好的书面测试还是难看？

1 个答案: