Question

我有两个data.frames：

# limits
   ID    Start_1      End_1    Start_2      End_2
1  A 2013-04-23 2013-06-09 2013-04-26 2017-02-06
2  B 2013-05-12 2013-08-08 2013-04-26 2017-02-06
3  C 2013-04-24 2013-04-26 2017-02-05 2017-02-08

和

# df (header shown)
   Timestamp          ID
1 2013-04-24 14:01:21  A
2 2013-04-24 14:01:46  B
3 2013-04-24 14:01:50  C
4 2013-04-25 00:02:19  A
5 2013-04-25 02:02:48  B
6 2013-04-25 04:02:04  C

我想根据观察结果的时间戳（Pop）填充data.frame df中的列df$Timestamp：如果df$Timestamp介于两个时间限制之间（存储在data.frame，limits：limits$Start_1和limits$End_1）中，Pop列填充“是”，否则填充“否”。

如果df$Timestamp介于两个下一个时间限制（limits$Start_2和limits$End_2）之间，则Pop列会填充'可能'，覆盖任何“是”或'否'。

设置如下：

# main data.frame
df<-structure(list(Timestamp = structure(c(1366826481, 1366826506,
                                           1366826510, 1366862539, 1366869768, 1366876924, 1366948927, 1366948963,
                                           1367013725, 1367107304, 1367107308, 1367107316, 1486342833, 1486350011,
                                           1486350026, 1486429233, 1486436435, 1486436459, 1486515633, 1486522816,
                                           1486522834, 1486530052, 1486537217, 1486537251),
                                         class = c("POSIXct","POSIXt"), tzone = ""),
                   ID = structure(c(1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L,1L, 2L, 3L),
                                  .Label = c("A", "B", "C"), class = "factor")),
              .Names = c("Timestamp", "ID"), row.names = c(NA, -24L), class = "data.frame")  

# data.frame with time limits
limits<- structure(list(ID = structure(1:3, .Label = c("A", "B", "C"), class = "factor"),
                    Start_1 = structure(c(1366689600, 1368331200, 1366776000), class = c("POSIXct","POSIXt"), tzone = ""),
                    End_1 = structure(c(1370750400, 1375934400,1366948800), class = c("POSIXct", "POSIXt"), tzone = ""),
                    Start_2 = structure(c(1366948800, 1366948800, 1486270800), class = c("POSIXct", "POSIXt"), tzone = ""),
                    End_2 = structure(c(1486357200, 1486357200, 1486530000), class = c("POSIXct", "POSIXt"), tzone = "")),
               .Names = c("ID","Start_1", "End_1", "Start_2", "End_2"),
               row.names = c(NA,-3L), class = "data.frame")

我有两种似乎有效的方法，但它们很麻烦，对于现实生活中的数据集（数千行，数百ID，以及多个$Start和$End期间对于相同的ID），它们很难“信任”它们的工作。

###### Method 1 ######
df1<-df
df1<-left_join(df1, limits, by="ID")

df1$Pop<-ifelse(df1$Timestamp>as.POSIXct(df1$Start_1) &
                 df1$Timestamp<as.POSIXct(df1$End_1), "Yes", "No")
df1$Pop<-ifelse(df1$Timestamp>as.POSIXct(df1$Start_2) &
                         df1$Timestamp<as.POSIXct(df1$End_2), "Maybe", df1$Pop)
df1$Pop<-as.factor(df1$Pop)
df1<-df1[,-c(3,6)]

###### Method 2 ######
df2<-df
df2<-df2[with(df2, order(ID, Timestamp)), ]
ids<-as.factor(levels(droplevels(df2$ID)))
tmp<-NULL
for(i in 1:length(ids)) {
  tmp[[i]]<-ifelse(df2$Timestamp[which(df2$ID==ids[i])]> as.POSIXct(limits$Start_1[i]) &
                     df2$Timestamp[which(df2$ID==ids[i])]< as.POSIXct(limits$End_1[i]), "Yes", "No") }
tmp<-data.frame(Pop = unlist(tmp)) # tmp is a list - this turns it into a data-frame
df2<-cbind(df2,tmp)

# add 'Maybe'
tmp2<-NULL
for(i in 1:length(ids)) {
  tmp2[[i]]<-df2$Timestamp[which(df2$ID==ids[i])]> as.POSIXct(limits$Start_2[i]) & 
    df2$Timestamp[which(df2$ID==ids[i])]< as.POSIXct(limits$End_2[i]) }
tmp2<-data.frame(Pop = unlist(tmp2))
df2$Pop<-as.character(df2$Pop)
df2$Pop[which(tmp2$Pop==TRUE)]<-'Maybe'
df2$Pop<-as.factor(df2$Pop)
df2<-df2[with(df2, order(Timestamp)), ]

是否有更优雅的方式（使用函数，包）来进行这种连接？

编辑：
在方法1的ifelse()中，我使用limits$Start_1，limits$End_1等代替df1$Start1，df1$End_1等。

Answer 1

YGS，这是一个data.table解决方案（使用上面的设置代码但使用＆＃34; as.data.table（）＆＃34;围绕data.frames）。也从您的解决方案中假设您确实需要＆＃34;可能＆＃34;覆盖是/否答案。

library(data.table)

#Set keys on ID's for join
setkey(df, ID)
setkey(limits, ID)

#Join the data.tables on ID
DT <- df[limits]

#Create "pop" column and chain to desired columns from user output
DT <- DT[, ':=' (Pop = ifelse(Timestamp > Start_2 & Timestamp < End_2, "Maybe",
                         ifelse(Timestamp > Start_1 & Timestamp < End_1, "Yes","No")))][, c(1,2,5,6,7)]

更新：更优雅：

#Create "pop" column

DT <- df[limits, ':=' (Pop = ifelse(Timestamp > Start_2 & Timestamp < End_2, "Maybe",
                              ifelse(Timestamp > Start_1 & Timestamp < End_1, "Yes","No"))), by = .EACHI, on = "ID"]

R：基于时间戳间隔

1 个答案: