Question

let smallestgrade = (min(musicgrade, bildgrade, matematicsgrade))  (Dosent work)

等级的替代方案是：“A，B，C，D，E，F”

F是最小值，其值为0

A是最大值，值为20

如何整理出最小的值？我可以这样做：

A = 20

B = 17.5

C = 15.0

D = 12.5

E = 10

F = 0

...

Answer 1

简单，类型安全的解决方案：

enum Grade : Double {
    case A = 20.0
    case B = 17.5
    case C = 15.0
    case D = 12.5
    case E = 10.0
    case F = 0.0
}

extension Grade : Comparable {
    static func <(lhs: Grade, rhs: Grade) -> Bool {
        return lhs.rawValue < rhs.rawValue
    }
}

let musicGrade = Grade.A
let bildGrade = Grade.E
let mathGrade = Grade.D

let worstGrade = [musicGrade, bildGrade, mathGrade].min()
print(worstGrade)

Answer 2

也许你想要这样的事情：

let gradeValues = ["A" : 20, "B" : 17.5, "C" : 15.0, "D" : 12.5, "E" : 10, "F" : 0]
let grades = ["B", "A", "C", "A", "B"]
let minim = grades.min {gradeValues[$0]! < gradeValues[$1]!} // "C"

如何获得字符串的最小值和最高值？

2 个答案: