Question

假设有一个字符串“johngoestoschool”它应该变成“JoHnGoEsToScHoOl”并且如果它之间存在特殊字符则应该忽略它，例如给定字符串“jo $％@＃hn ^ g oe！st＃os＆amp; ch oo）l“答案应为”Jo $％@＃Hn ^ G oE！sT＃oS＆amp; cH oO）l“

从this回答，我们为了迭代我们可以做到：

let s = "alpha"
for i in s.characters.indices[s.startIndex..<s.endIndex]
{
    print(s[i])
}

为什么我们不能在这里打印“i”的值？当我们执行i.customPlaygroundQuickLook时，它键入int 0到int4。

所以我的想法是

if (i.customPlaygroundQuickLook == 3) {
        s.characters.currentindex = capitalized
}

请帮助

Answer 1

这应该解决你的功能，困难的部分只是检查天气是否是字母是字母，使用inout并且替换范围会提供更好的性能：

func altCaptalized(string: String) -> String {
    var stringAr = string.characters.map({ String($0) }) // Convert string to characters array and mapped it to become array of single letter strings
    var numOfLetters = 0

    // Convert string to array of unicode scalar character to compare in CharacterSet
    for (i,uni) in string.unicodeScalars.enumerated() {
        //Check if the scalar character is in letter character set
        if CharacterSet.letters.contains(uni) { 
            if numOfLetters % 2 == 0 {
                stringAr[i] = stringAr[i].uppercased() //Replace lowercased letter with uppercased
            }
            numOfLetters += 1
        }
    }

    return stringAr.joined() //Combine all the single letter strings in the array into one string
}

如何大写字符串的每个替代字符？

1 个答案: