我有这张桌子
Id PId Name Value
------------------------
1 null foo null
2 1 bar null
3 2 foobar hi
4 1 bar1 hey
我需要一个可以给我这个结果的查询:
Name | Value
-----------------------
foo bar foobar | hi
foo bar1 | hey
答案 0 :(得分:0)
with s( id, pid, name, value) as
(
select f.id, f.pid, cast(f.name as nvarchar) as name, f.value from foos f
where f.pid is null
union all
select f.id, f.pid, cast(s.name + f.name as nvarchar) as name, f.value from foos f inner join s on f.pid = s.id
)
select * from s
where not exists(select * from foos where pid = s.id)