我正在尝试在SQL Server中创建分层查询。
我有4张桌子：
Org3是最高级别，而org 6是最低级别。如您所见，org6在org5表中具有一个父ID，在org4表中具有一个父ID，在org3表中具有一个父ID。
父母可能没有孩子。
所以说我在表中有这些值：
Org3 表
| org3_id | org3_name |
+---------+-----------+
| 1 | MS |
| 2 | NS |
Org4 表
| org4_id | org4_name | org4_org3id |
+---------+-----------+-------------+
| 1 | TS | 1 |
| 2 | QS | 1 |
| 3 | BS | 1 |
Org5 表
| org5_id | org5_name | org5_org4id |
+---------+-----------+-------------+
| 1 | LS | 1 |
| 2 | PS | 1 |
| 3 | VS | 2 |
Org6 表
| org6_id | org6_name | org6_org5id |
+---------+-----------+-------------+
| 1 | AS | 1 |
| 2 | RS | 1 |
| 3 | ZS | 2 |
我想要得到的结果是：
| org3_id | org3_name | org4_id | org4_name | org5_id | org5_name | org6_id | org6_name | path |
|---------|-----------|---------|-----------|---------|-----------|---------|-----------|-------------|
| 1 | MS | NULL | NULL | NULL | NULL | NULL | NULL | MS |
| 1 | MS | 1 | TS | NULL | NULL | NULL | NULL | MS\TS |
| 1 | MS | 1 | TS | 1 | LS | NULL | NULL | MS\TS\LS |
| 1 | MS | 1 | TS | 1 | LS | 1 | AS | MS\TS\LS\AS |
| 1 | MS | 1 | TS | 1 | LS | 2 | RS | MS\TS\LS\RS |
| 1 | MS | 1 | TS | 2 | PS | NULL | NULL | MS\TS\PS |
| 1 | MS | 1 | TS | 2 | PS | 3 | ZS | MS\TS\PS\ZS |
| 1 | MS | 2 | QS | NULL | NULL | NULL | NULL | MS\QS |
| 1 | MS | 2 | QS | 3 | VS | NULL | NULL | MS\QS\VS |
| 1 | MS | 3 | BS | NULL | NULL | NULL | NULL | MS\BS |
| 2 | NS | NULL | NULL | NULL | NULL | NULL | NULL | NS |
这是我尝试过的。
SELECT
org3.org3_id,
org3.org3_name,
org3.org3_open_ind,
org4.org4_id,
org4.org4_name,
org4.org4_open_ind,
org5.org5_id,
org5.org5_name,
org5.org5_open_ind,
org6.org6_id,
org6.org6_name,
org6.org6_open_ind,
CONCAT(org3.org3_abbrv, '\', org4.org4_abbrv,
CASE
WHEN org5.org5_abbrv IS NULL THEN ''
ELSE CONCAT('\', org5.org5_abbrv)
END,
CASE
WHEN org6.org6_abbrv IS NULL THEN ''
ELSE CONCAT('\', org6.org6_abbrv)
END) AS [ORG PATH]
FROM
(SELECT
*
FROM
TSTAFFORG3
WHERE
org3_open_ind = 1) org3
LEFT OUTER JOIN
(SELECT
*
FROM
TSTAFFORG4
WHERE
org4_open_ind = 1) org4 ON org4.org4_org3id = org3.org3_id
LEFT OUTER JOIN
(SELECT
*
FROM
TSTAFFORG5
WHERE
org5_open_ind = 1) org5 ON org5.org5_org4id = org4.org4_id
LEFT OUTER JOIN
(SELECT
*
FROM
TSTAFFORG6
WHERE
org6_open_ind = 1) org6 ON org6.org6_org5id = org5.org5_id
ORDER BY
org3.org3_name, org4.org4_name, org5.org5_name, org6.org6_name
我认为也许需要CTE查询，但是在这种情况下我不确定如何对其进行构架。如果所有表都在一个表中，我想我可以弄清楚，但是由于它是多个表，所以我很难弄清SQL。我尝试的查询不只显示父级。它只会显示org3有子级的结果。
答案 0 :(得分：2)
这是一个可能的解决方案，但我不是它会如何执行。基本上是在所有级别上添加一个空行。
SELECT
org3.org3_id,
org3.org3_name,
org3.org3_open_ind,
org4.org4_id,
org4.org4_name,
org4.org4_open_ind,
org5.org5_id,
org5.org5_name,
org5.org5_open_ind,
org6.org6_id,
org6.org6_name,
org6.org6_open_ind,
CONCAT
(
org3.org3_name,
'\' + org4.org4_name,
'\' + org5.org5_name,
'\' + org6.org6_name
) AS [ORG PATH]
FROM TSTAFFORG3 org3
CROSS APPLY
(
SELECT org4_id, org4_name, org4_open_ind, org4_org3id
FROM TSTAFFORG4
WHERE org4_open_ind = 1
AND org4_org3id = org3.org3_id
UNION ALL
SELECT NULL, NULL, NULL, org3.org3_id
) org4
CROSS APPLY
(
SELECT org5_id, org5_name, org5_open_ind, org5_org4id
FROM TSTAFFORG5
WHERE org5_open_ind = 1
AND org5_org4id = org4.org4_id
UNION ALL
SELECT NULL, NULL, NULL, org4.org4_id
) org5
OUTER APPLY
(
SELECT org6_id, org6_name, org6_open_ind, org6_org5id
FROM TSTAFFORG6
WHERE org6_open_ind = 1
AND org6_org5id = org5.org5_id
UNION ALL
SELECT NULL, NULL, NULL, org4.org4_id
) org6
WHERE
org3_open_ind = 1
ORDER BY
org3.org3_name, org4.org4_name, org5.org5_name, org6.org6_name;
如果其他人有不同的想法，我将样本数据保留为可消耗格式。
CREATE TABLE TSTAFFORG3(
org3_id int,
org3_name varchar(10),
org3_open_ind bit);
INSERT INTO TSTAFFORG3
VALUES
( 1, 'MS', 1),
( 2, 'NS', 1);
CREATE TABLE TSTAFFORG4(
org4_id int,
org4_name varchar(10),
org4_org3id int,
org4_open_ind bit);
INSERT INTO TSTAFFORG4
VALUES
( 1, 'TS', 1, 1),
( 2, 'QS', 1, 1),
( 3, 'BS', 1, 1);
CREATE TABLE TSTAFFORG5(
org5_id int,
org5_name varchar(10),
org5_org4id int,
org5_open_ind bit);
INSERT INTO TSTAFFORG5
VALUES
( 1, 'LS', 1, 1),
( 2, 'PS', 1, 1),
( 3, 'VS', 2, 1);
CREATE TABLE TSTAFFORG6(
org6_id int,
org6_name varchar(10),
org6_org5id int,
org6_open_ind bit);
INSERT INTO TSTAFFORG6
VALUES
( 1, 'AS', 1, 1),
( 2, 'RS', 1, 1),
( 3, 'ZS', 2, 1);
答案 1 :(得分：1)
要清楚：您正在对分层数据建模。在RDBMS中有多种存储分层数据的方法。两个是：
TS/MS/RS）。您的数据模型似乎有问题：如果要添加另一个级别，是否要添加新表？
如果可以的话，应将所有内容移到一张表中：
orgs(org_id, org_name, parent_org)
这使用邻接列表方法。
然后，您可以创建一个简单的递归CTE（或多个自联接）来获得具体的路径。
避开组织ID（如果将所有内容放在一张表中则必须重新生成），以下查询将为您提供以下结果：
WITH
-- sample data (I'm only using org names, not org IDs).
Orgs(org_name, parent_org) AS
(
SELECT * FROM
(
VALUES
('MS', NULL),
('NS', NULL),
('TS', 'MS'),
('QS', 'MS'),
('BS', 'MS'),
('LS', 'TS'),
('PS', 'TS'),
('VS', 'QS'),
('AS', 'LS'),
('RS', 'LS'),
('ZS', 'PS')
) v(c1, c2)
),
-- hierarchical/recursive CTE
OrgsWithPath(org_name, parent_org, org_path) AS
(
SELECT org_name, parent_org, CAST(org_name AS VARCHAR(MAX))
FROM Orgs
WHERE parent_org IS NULL
UNION ALL
SELECT Orgs.org_name, Orgs.parent_org, OrgsWithPath.org_path + '\' + Orgs.org_name
FROM OrgsWithPath
INNER JOIN Orgs ON
Orgs.parent_org = OrgsWithPath.org_name
)
SELECT * FROM OrgsWithPath ORDER BY org_path
+----------+------------+-------------+ | org_name | parent_org | org_path | +----------+------------+-------------+ | MS | NULL | MS | | BS | MS | MS\BS | | QS | MS | MS\QS | | VS | QS | MS\QS\VS | | TS | MS | MS\TS | | LS | TS | MS\TS\LS | | AS | LS | MS\TS\LS\AS | | RS | LS | MS\TS\LS\RS | | PS | TS | MS\TS\PS | | ZS | PS | MS\TS\PS\ZS | | NS | NULL | NS | +----------+------------+-------------+
请注意最后一个ORDER BY中的SELECT：这确定您的查询是深度优先（遍历完整路径）还是广度优先（从所有顶级节点开始，然后进行）。通过这种方法，包含一个“级别”也很容易，因此您知道它是顶级节点还是其他级别。
获取其他列比较麻烦，但也可以由递归CTE处理（使用CASE和COALESCE）：
WITH
OrgsWithPath(org_name, org_path, org_level, org3_name, org4_name, org5_name, org6_name) AS
(
SELECT
Orgs.org_name,
CAST(org_name AS VARCHAR(MAX)),
1,
Orgs.org_name,
CAST(NULL AS VARCHAR(255)),
CAST(NULL AS VARCHAR(255)),
CAST(NULL AS VARCHAR(255))
FROM Orgs
WHERE parent_org IS NULL
UNION ALL
SELECT
Orgs.org_name,
OrgsWithPath.org_path + '\' + Orgs.org_name,
OrgsWithPath.org_level + 1,
OrgsWithPath.org3_name,
CASE WHEN OrgsWithPath.org_level+1 >= 2 THEN COALESCE(OrgsWithPath.org4_name, Orgs.org_name) END,
CASE WHEN OrgsWithPath.org_level+1 >= 3 THEN COALESCE(OrgsWithPath.org5_name, Orgs.org_name) END,
CASE WHEN OrgsWithPath.org_level+1 >= 4 THEN COALESCE(OrgsWithPath.org6_name, Orgs.org_name) END
FROM OrgsWithPath
INNER JOIN Orgs ON
Orgs.parent_org = OrgsWithPath.org_name
)
SELECT *
FROM OrgsWithPath
ORDER BY org_path
+----------+-------------+-----------+-----------+-----------+-----------+-----------+ | org_name | org_path | org_level | org3_name | org4_name | org5_name | org6_name | +----------+-------------+-----------+-----------+-----------+-----------+-----------+ | MS | MS | 1 | MS | NULL | NULL | NULL | | BS | MS\BS | 2 | MS | BS | NULL | NULL | | QS | MS\QS | 2 | MS | QS | NULL | NULL | | VS | MS\QS\VS | 3 | MS | QS | VS | NULL | | TS | MS\TS | 2 | MS | TS | NULL | NULL | | LS | MS\TS\LS | 3 | MS | TS | LS | NULL | | AS | MS\TS\LS\AS | 4 | MS | TS | LS | AS | | RS | MS\TS\LS\RS | 4 | MS | TS | LS | RS | | PS | MS\TS\PS | 3 | MS | TS | PS | NULL | | ZS | MS\TS\PS\ZS | 4 | MS | TS | PS | ZS | | NS | NS | 1 | NS | NULL | NULL | NULL | +----------+-------------+-----------+-----------+-----------+-----------+-----------+