Question

我有一个电子表格，其列为：1,2,3,5 ... 100。

在我的代码中，我可以搜索每一列。上面的列是第8列。我希望能够打印行值和它下面的行。我用过：

print row[8 + 1]

所有这些似乎都是打印行值，然后添加一个。但是，我想要做的是使用：

print row[8]
print row[8 + 1]

哪个会打印出一个值和

下面的值

完整代码：

i

mport csv
import string

with open("testercsv.csv", "rb") as f:
    reader = csv.reader(f)
    #Error log file
    log_error = open("lewis.txt", 'a')
    #Checking row 
    next(f, None)
    next(f, None)
    for row in reader:
        #row 1
        if (row[1]) == "2":
            print "Found: ", "2"
        else:
            log_error.write("Found: ")
            log_error.write(row[1])
            log_error.write(" Expected: 2")
            log_error.write("\n")
        #row 2  
        if (row[2]) == "0":
            print "Found: ", "0"
        else:
            print "0 error"
        #row 3
        if (row[3]) == "LIVE":
            print "Found: ", "LIVE"
        else:
            print "LIVE error"
        #row 4  
        if (row[4]) == "2":
            print "Found: ", "2"
        else:
            print "2 error"
        #row 5  
        if (row[5]) == "0":
            print "Found: ", "0"
        else:
            print "0 error"
        #row 6
        if (row[6]) == "1":
            print "Found: ", "1"
        else:
            print "1 error"
        #row 7
        if (row[7]) == "0":
            print "Found: ", "0"
        else:
            print "0 error"
        #Checking count row 8

        print row[8+1]

Answer 1

    for i in range(0,100):
        print(row[i])
        print(row[i+1])

Python：在同一循环中搜索下一列[CSV]

1 个答案: