我有一个json字符串字符串,我想从中获取值。它是密钥对形式,所以我想要每个密钥的值。
我试图获得价值,但我没有得到它。
Json String就像:
{
"document": {
"xmlns:xsi": "http:\/\/www.w3.org\/2001\/XMLSchema-instance",
"xsi:schemaLocation": "http:\/\/ocrsdk.com\/schema\/recognizeard-1.0.xsd http:\/\/ocrsdk.com\/schema\/recognized-1.0.xsd",
"xmlns": "http:\/\/ocrsdk.com\/schema\/recognize-1.0.xsd",
"businessCard": {
"imageRotation": "noRotation",
"field":
[{
"type": "Name",
"value": "Rafcev B. Agnrwal"
}, {
"type": "Company",
"value": "VJ>"
}, {
"type": "Text",
"value": "Dr. Rafcev B. Agnrwal\nMOB 0324%\nun\n) AOM*. founts. sso\nVJ>\nT"
}]
}
}
}
我希望得到"姓名","地址","公司"等
我试着这样:
JSONArray array;
if(mIntent.getStringExtra("jsonString") != null) {
Log.d("json", mIntent.getStringExtra("jsonString"));
try {
JSONObject object = new JSONObject(mIntent.getStringExtra("jsonString"));
array = object.getJSONArray("field");
for (int i = 0; i < array.length(); i++) {
JSONObject subObject1 = array.getJSONObject(i);
edt_FirstName.setText(object.getString("Name"));
}
} catch (JSONException e) {
}
有人可以帮帮我吗?谢谢..
编辑:
我试图检查这样的值:
for (int i = 0; i < array.length(); i++) {
JSONObject subObject1 = array.getJSONObject(0);
String type = subObject1.getString("type");
String value = subObject1.getString("value");
if (type.equals("Name")) {
edt_FirstName.setText(value);
}
if(type.equals("Address"))
{
edt_address.setText(value);
}
if(type.equals("Company"))
{
edt_company.setText(value);
}
if(type.equals("Mobile"))
{
edt_Mobile.setText(value);
}
}
我想从字段数组中获取所有值并设置为文本视图,但我只获取Name值而不是其他值。
此外,我可以获得两个像Mobile这样的两个字段,我可以获得两次,所以我想结合两个Mobile值并显示它。
答案 0 :(得分:3)
所以你的json对象如下:
{
"document": {
"xmlns:xsi": "http:\/\/www.w3.org\/2001\/XMLSchema-instance",
"xsi:schemaLocation": "http:\/\/ocrsdk.com\/schema\/recognizeard-1.0.xsd http:\/\/ocrsdk.com\/schema\/recognized-1.0.xsd",
"xmlns": "http:\/\/ocrsdk.com\/schema\/recognize-1.0.xsd",
"businessCard": {
"imageRotation": "noRotation",
"field":
[{
"type": "Name",
"value": "Rafcev B. Agnrwal"
}, {
"type": "Company",
"value": "VJ>"
}, {
"type": "Text",
"value": "Dr. Rafcev B. Agnrwal\nMOB 0324%\nun\n) AOM*. founts. sso\nVJ>\nT"
}]
}
}
}
首先需要将“文档”设为JSONObject
,然后将“businessCard”设为JSONObject
,然后将“字段”设为JSONArray
:
if(mIntent.getStringExtra("jsonString") != null) {
Log.d("json", mIntent.getStringExtra("jsonString"));
try {
JSONObject object = new JSONObject(mIntent.getStringExtra("jsonString"));
JSONArray array = object.getJSONObject("document").getJSONObject("businessCard").getJSONArray("field");
for (int i = 0; i < array.length(); i++) {
JSONObject subObject = array.getJSONObject(i);
String type = subObject.getString("type");
String value = subObject.getString("value");
if (type.equals("Name")) {
String prevValue = edt_FirstName.getText();
edt_FirstName.setText((TextUtils.isEmpty(prevValue) ? "" : prevValue + ",") + value);
}
}
} catch (JSONException e) { }
}
答案 1 :(得分:1)
试试这段代码,希望它会对你有帮助。
try
{
JSONObject jsonObject = new JSONObject();
JSONObject documentObject = jsonObject.getJSONObject("document");
JSONObject businessCardObject = documentObject.getJSONObject("businessCard");
String imgRotation = businessCardObject.getString("imageRotation");
JSONArray array = businessCardObject.getJSONArray("field");
for (int i = 0; i < array.length() ; i++)
{
JSONObject arrObj = array.getJSONObject(i);
String type = arrObj.getString("type");
String value = arrObj.getString("value");
Log.e(TAG, "type=="+type);
Log.e(TAG, "value=="+value);
}
}
catch (Exception ex)
{
ex.printStackTrace();
}