从json字符串中获取值

Question

我从JSON中提取值，但在回显值

时继续获得空结果

$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';

$obj2 = json_decode($json, true);

$displayName = $obj2->Surname;

echo"$displayName";

Answer 1

你在这个json字符串

中的另一个对象中有一个对象

$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';

$obj2 = json_decode($json);

print_r($obj2);

Answer 2

试试这个：

<?php
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$obj2 = json_decode($json, true);
$displayName = $obj2[0][0]['Surname'];
echo "$displayName";
?>

Answer 3

这应该是这样的：

$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address    Line 1":"RG412GX"}]]';

$obj2 = json_decode($json, true);

$displayName = $obj2->Surname;

echo"$displayName";

你正在混淆/组成变量名......

Answer 4

您提供的代码存在一些问题。 首先，您的json文本存储在$json中，但您尝试解码$xmlresponse。我想这只是一个复制/粘贴错误。 其次，您尝试使用对象语法访问姓氏，尽管您明确强制json_decode将对象解码为关联数组。 第三，json提供了在数组中的数组中编码对象。您忽略响应的嵌套结构。

试试这个：

$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$response = json_decode($json);
$displayName = $response[0][0]->Surname;

echo $displayName;