Question

这是我的代码，我不断收到错误。我能够成功识别无效的整数。但是，如果我输入正数，我会收到此错误TypeError：并非在字符串格式化期间转换所有参数。

inter=(input('Enter a positive integer:'))
if not inter.isdigit():
    print('You did not enter a valid input!')
else:
    if(inter%2==0):
        print('You entered an even number')
    elif(inter%7==0):
        print('You entered an odd number that is a multiple of 7')
    else:
        print('You entered an odd number that is NOT a multiple of 7')

Answer 1

inter=(input('Enter a positive integer:'))
if not inter.isdigit():
print('You did not enter a valid input!')
else:
if(int(inter)%2==0):
    print('You entered an even number')
elif(int(inter)%7==0):
    print('You entered an odd number that is a multiple of 7')
else:
    print('You entered an odd number that is NOT a multiple of 7')

Answer 2

try:
    inter=int((input('Enter a positive integer:')))
    if(inter%2==0):
        print('You entered an even number')
    elif(inter%7==0):
        print('You entered an odd number that is a multiple of 7')
    else:
        print('You entered an odd number that is NOT a multiple of 7')
except:    
    print('You did not enter a valid input!')

这是查看输入是否为int的更好方法。 try-except语句处理任何错误。如果尝试遇到错误，那么它将突破该语句并执行except语句。因此，当输入转换为int时，如果输入是字符串，则会引发错误。

输入正整数时输入Error

2 个答案: