我正在尝试对SF Bay Area Bike Share Kaggel数据
中的数据执行一些SQL当我运行此SQL时:
/****** Select Bikes ******/
SELECT count(t.[id]) as TripCount
,t.[bike_id]
FROM [dbo].[trip] t
Group By t.[bike_id]
having count(t.[id]) < 25
Order By TripCount asc
我得到了这个结果:
+-----------+---------+
| TripCount | bike_id |
+-----------+---------+
| 6 | 876 |
| 18 | 323 |
| 20 | 565 |
| 24 | 476 |
| 24 | 697 |
+-----------+---------+
我真正想要的是:
+-----------+---------+------------+------------+
| TripCount | bike_id | Min_date | Max_date |
+-----------+---------+------------+------------+
| 6 | 876 | 2014-05-22 | 2014-05-27 |
| 18 | 323 | 2013-08-30 | 2013-09-07 |
| 20 | 565 | 2013-08-29 | 2013-09-07 |
| 24 | 476 | 2013-08-29 | 2013-09-07 |
| 24 | 697 | 2013-10-15 | 2013-12-20 |
+-----------+---------+------------+------------+
最小日期&amp;最大日期分别给出第一个&amp;自行车去旅行的最后日期。
我可以通过运行以下方法为每辆自行车手动执行此操作:
SELECT
min(cast([start_date] as date)) as Min_Date
,max(cast([start_date] as date)) as Max_Date
,[bike_id]
FROM [dbo].[trip]
where bike_id = '697'
Group By bike_id
我尝试了这个查询:
/****** Script for SelectTopNRows command from SSMS ******/
SELECT
count (t.[id]) as TripCount
,min(cast(t.[start_date] as date)) as Min_Date
,max(cast(t.[start_date] as date)) as Max_Date
,[bike_id]
FROM [dbo].[trip] t
Group By count (t.[id]), bike_id
并且显然出现以下错误: 不能在GROUP BY子句列表的组表达式中使用聚合或子查询。
只是不太确定如何绕过这个......
答案 0 :(得分:1)
你很亲密
SELECT
[bike_id]
,count (t.[id]) as TripCount
,min(cast(t.[start_date] as date)) as Min_Date
,max(cast(t.[start_date] as date)) as Max_Date
FROM [dbo].[trip] t
Group By bike_id