Question

我在PHP中遇到了一个奇怪的问题。我有一个包含一些整数值的数组。当我尝试将数组中的值与目标整数进行比较时，索引不能与数组一起使用，也不能递增。这是一个例子。

问题出在if（$ j == $ indexOfExposed [$ k]）

/*  This is a simple function to show some letters of a patient name, while the rest of letters are replaced with asterisks.
    @Param: Patient name
    @Return: limited preview of patient name;
*/
function encodeName($name){

    $len = strlen($name);                       // This is the lenghth of $name. used to itterate and set a range.
    $numOfExposedLetters = rand(1, 4);          // Random value assigned to see how many letters of the name will be exposed.
    $indexOfExposed = array();                  // This is an array of indexes for exposed letters.
    $k = 0;                                     // This counter is used to traverse the $indexOfExposed array.
    $encodedName = "";                          // This is the value we will return after it is generated.
    $previous = 0;                              // Used to keep track of previous value in the $indexOfExposed array. This is incase we have repeated values in the array;

    /*  This loop is used to append random values to the arary of indexes,
        With $numOfExposedLetters being the quantity of exposed letters.    */
    for($i = 0; $i < $numOfExposedLetters; $i++){
        $indexOfExposed[$i] = rand(2, $len);
    }
    sort($indexOfExposed);                      // Sort the array, for easier access.


    /* Ecoding name */
    for($j = 1; $j <= $len; $j++){

        if($indexOfExposed[$k] == $previous){
            $encodedName .= "*";
            $k++;
            continue;
        }

        if($j == $indexOfExposed[$k]){
            $encodedName .= $name[$j-1];
            $previous = $indexOfExposed[$k];
            $k++;
        }

        else
            $encodedName .= "*";
            $k++;

    }   // end of encode

    return $encodedName;

}

此代码采用人名，并用星号替换名称中的字母。随机索引，公开名称中的实际字母。

Answer 1

调试代码是一项繁琐的工作，不值得。我建议你一个替代实现，希望使用你想到的算法，更容易阅读和理解，并可能运行得更快。

function encodeName($name)
{
    $len = strlen($name);
    $numOfExposedLetters = rand(1, 4);
    $encodedName = str_repeat('*', $len);
    while ($numOfExposedLetters --) {
        $index = rand(2, $len - 1);
        $encodedName[$index] = $name[$index];
    }

    return $encodedName;
}

数组的索引不提取数组中的正确元素PHP

1 个答案: