我有一个数组.my数组存储在
中$details = $this->api_model->testw();
此处mysql查询返回$details
中的结果数组。
现在我想保留第一个索引日期时间值和最后一个索引日期时间值
喜欢
$first='2010-05-15 11:29:45';
$last='2010-05-26 16:04:24';
我的数组
Array
(
[0] => Array
(
[id] => 2
[type] => comment
[text] => hey
[datetime] => 2010-05-15 11:29:45
)
[1] => Array
(
[id] => 3
[type] => status
[text] => oi
[datetime] => 2010-05-26 15:59:53
)
[2] => Array
(
[id] => 4
[type] => status
[text] => yeww
[datetime] => 2010-05-26 16:04:24
)
)
答案 0 :(得分:0)
使用end()
和reset()
获取第一个和最后一个数组,然后访问datetime
值,如下所示:
// Get the first and last sub-arrays
$first = reset($data);
$last = end($data);
// Create an array containing the datetimes
$result = array($first['datetime'], $last['datetime']);
// Output the contents of the above array
print_r($result);
输出:
Array
(
[0] => 2010-05-15 11:29:45
[1] => 2010-05-26 16:04:24
)
答案 1 :(得分:0)
试试这个:
<?php
$Arr = Array(Array('id' => 2, 'type' => 'comment', 'text' => 'hey', 'datetime' => '2010-05-15 11:29:45'), Array('id' => 3, 'type' => 'status', 'text' => 'oi', 'datetime' => '2010-05-26 15:59:53'), Array('id' => 4, 'type' => 'status', 'text' => 'yeww', 'datetime' => '2010-05-26 16:04:24'));
$count = 0;
$totalcount = count($Arr);
foreach ($Arr as $Arr1) {
$count++;
if ($count == 1 || $count == $totalcount) {
foreach ($Arr1 as $key1 => $val2) {
if ($count == 1 && $key1 == 'datetime')
$first = $val2;
if ($count == $totalcount && $key1 == 'datetime')
$last = $val2;
}
}
}
echo $first.' - '.$last;
?>
答案 2 :(得分:0)
使用end()和reset()访问数组的第一个和最后一个元素,然后访问日期时间值。
// Get the first and last element of array
$ first = reset($ data); $ last = end($ data);