一些强类型的课程:
public class A
{
public C Process(B b)
{
return new C()
{
Output = b.Property + " bar!"
};
}
}
public class B
{
public string Property {get;set;}
}
public class C
{
public string Output {get;set;}
}
以JSON字符串输入:
string input = "{\"Property\":\"foo\"}";
我想要的是如果我有A的实例作为对象,我想调用这个JSON并检索对象输出:
object instanceOfA = new A();
object result = instanceOfA.GetType().GetMethod("Process").Invoke(instanceOfA, new []{ /*json here?*/});
因此,它基本上类似于某些普通参数上的一些JavaScript调用。
答案 0 :(得分:1)
如何更改“Process”方法的方法签名,而不是将字符串作为输入,并尝试将输入反序列化为您想要的类型?所以像这样:
string input = "{\"Property\":\"foo\"}";
object instanceOfA = new A();
object result = instanceOfA.GetType().GetMethod("Process").Invoke(instanceOfA, new object[]{ input });
public class A
{
public C Process(string input)
{
var b = (B) JsonConvert.DeserializeObject(input, typeof(B));
if (!string.IsNullOrEmpty(b.Property))
{
return new C()
{
Output = b.Property + " bar!"
};
}
return null;
}
}
public class B
{
public string Property { get; set; }
}
public class C
{
public string Output { get; set; }
}
答案 1 :(得分:1)
使用Newtonsoft.Json功能解决问题:
public class JsonInvoker
{
private readonly MethodInfo _methodInfo;
private readonly Type _paramType;
private readonly JsonSerializerSettings _settings;
public JsonInvoker(Type instanceType, string methodName)
{
_methodInfo = instanceType.GetMethod(methodName);
_paramType = _methodInfo.GetParameters()[0].ParameterType;
_settings = new JsonSerializerSettings
{
ContractResolver = new RequireObjectPropertiesContractResolver(),
MissingMemberHandling = MissingMemberHandling.Error
};
}
public object Invoke(object instance, string json)
{
var input = JsonConvert.DeserializeObject(json, _paramType, _settings);
var output = _methodInfo.Invoke(instance, new[] { input });
return output;
}
private class RequireObjectPropertiesContractResolver : DefaultContractResolver
{
protected override JsonObjectContract CreateObjectContract(Type objectType)
{
var contract = base.CreateObjectContract(objectType);
contract.ItemRequired = Required.AllowNull;
return contract;
}
}
}
现在我可以调用我的方法:
class Program
{
static void Main(string[] args)
{
object plugin = new A();
string json = "{\"Property\":\"foo\"}";
var invoker = new JsonInvoker(plugin.GetType(), "Process");
//here I call invoker with simple string.
var output = invoker.Invoke(plugin, json);
}
}
public class A
{
public C Process(B input)
{
return new C
{
Property = input.Property + " bar"
};
}
}
public class C
{
public string Property { get; set; }
}
public class B
{
public string Property { get; set; }
}