Question

我正在尝试在Xml序列化期间添加命名空间。到目前为止，我添加了一些但我无法使用Xml序列化程序添加自定义命名空间。

到目前为止，我已经实现了这个

   <?xml version="1.0"?>
<manifest xmlns:xmlns="http://www.imsproject.org/xsd/imscp_rootv1p1p2e" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:adlcp="http://www.adlnet.org/xsd/adlcp_rootv1p2" xsi:schemaLocation="http://www.imsproject.org/xsd/imscp_rootv1p1p2 imscp_rootv1p1p2.xsd http://www.imsglobal.org/xsd/imsmd_rootv1p2p1 imsmd_rootv1p2p1.xsd http://www.adlnet.org/xsd/adlcp_rootv1p2 adlcp_rootv1p2.xs" identifier="test" version="2">
  <lom xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="test lom" xmlns="http://ltsc.ieee.org/xsd/LOM" />
  <resource adlcp:scormtype="sco" />
</manifest>

这是我的代码

清单类

[Serializable]
[XmlRoot(ElementName = "manifest")]
public class Manifest
{
    /// <summary>
    /// manifest root node
    /// </summary>
    [XmlAttribute(AttributeName = "identifier")]
    public string Identifier { get; set; }

    [XmlAttribute(AttributeName = "version")]
    public string Version { get; set; }

    //[XmlAttribute(AttributeName = "adlcp", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
    //public string Adlcp = "http://www.adlnet.org/xsd/adlcp_rootv1p2";

    [XmlAttribute(AttributeName = "schemaLocation", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
    public string SchemaLocation = "http://www.imsproject.org/xsd/imscp_rootv1p1p2 imscp_rootv1p1p2.xsd http://www.imsglobal.org/xsd/imsmd_rootv1p2p1 imsmd_rootv1p2p1.xsd http://www.adlnet.org/xsd/adlcp_rootv1p2 adlcp_rootv1p2.xs";


    [XmlElement(ElementName = "lom", Namespace = "http://ltsc.ieee.org/xsd/LOM")]
    public Lom Lom { get; set; }

    [XmlElement("resource")]
    public Resource Resource { get; set; }
}

Lom Class

 public class Lom
    {
        [XmlAttribute(AttributeName = "schemaLocation", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
        public string SchemaLocation { get; set; }

        [XmlAttribute(AttributeName = "xsi", Namespace = "http://www.imsproject.org/xsd/imscp_rootv1p1p2e")]
        public string Xsi = "http://www.w3.org/2001/XMLSchema-instance";


    }

资源类

 public class Resource
    {
        [XmlAttribute(AttributeName = "scormtype", Namespace = "http://www.adlnet.org/xsd/adlcp_rootv1p2")]
        public string ScormType { get; set; }
    }

我的序列化功能就像这样

using (FileStream fs = new FileStream(filePath, FileMode.Create))
        {
            var xmlSerializer = new XmlSerializer(typeof(Manifest));

        var ns = new XmlSerializerNamespaces();
        ns.Add("xmlns", "http://www.imsproject.org/xsd/imscp_rootv1p1p2e");
        ns.Add("adlcp", "http://www.adlnet.org/xsd/adlcp_rootv1p2");
        ns.Add("xsi", "http://www.w3.org/2001/XMLSchema-instance");
        xmlSerializer.Serialize(fs, data, ns);

        fs.Close();

    }

我需要这样的输出。

<?xml version="1.0"?>
    <manifest 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
    identifier="test" version="2" 
    xmlns:adlcp="test"
    xsi:schemaLocation="test location" 
    **xmlns="http://www.imsproject.org/xsd/imscp_rootv1p1p2"**>
      <lom 
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
      xsi:schemaLocation="http://ltsc.ieee.org/xsd/LOM lom.xsd" 
      xmlns="http://ltsc.ieee.org/xsd/LOM" />
     <resource adlcp:scormtype="sco"/>
    </manifest>

我做错了什么？

Answer 1

只需添加一个namspace序列化程序

            var xmlSerializer = new XmlSerializer(typeof(Manifest), "http://www.w3.org/2001/XMLSchema-instance");
            var ns = new XmlSerializerNamespaces();
            ns.Add("xmlns", "http://www.w3.org/2001/XMLSchema-instance");
            xmlSerializer.Serialize(fs, data, ns);

如果数据定义为

        Manifest data = new Manifest()
        { Identifier = "test", Version = "2", Adlcp = "test", SchemaLocation = "test location" };
        data.Resource = new Resource() { ScormType="sco" };

带有属性

    [XmlAttribute(AttributeName = "adlcp", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
    public string Adlcp { get; set; }

您将在输出中获得xmlns:adlcp="test"

同样的事情

    [XmlAttribute(AttributeName = "xsi", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
    public string Xsi = "http://www.w3.org/2001/XMLSchema-instance";

以及

            ns.Add("adlcp", "http://www.imsproject.org/xsd/Manifest/Adlcp");

与

    [XmlAttribute(AttributeName = "scormtype", Namespace = "http://www.imsproject.org/xsd/Manifest/Adlcp")]
    public string ScormType { get; set; }

获取可能的adlcp:scormtype="sco"

也可以在根类中添加名称空间，例如

[XmlRoot(ElementName = "manifest", Namespace = "http://www.imsproject.org/xsd/Manifest")]
public class Manifest

C＃Xml序列化属性添加自定义命名空间

1 个答案: